If IMHO = JNIP; IDK = JEL; and SO = TP, then IDC = __________.

The correct option is JED.

To find the code for IDC, we can analyze the pattern used in the given examples by observing how each letter is shifted in the English alphabet:

1. IMHO = JNIP:
I (+1) → J
M (+1) → N
H (+1) → I
O (+1) → P
Here, every letter is shifted forward by 1 position in the alphabetical order.

2. IDK = JEL:
I (+1) → J
D (+1) → E
K (+1) → L
Each letter is shifted forward by 1 position.

3. SO = TP:
S (+1) → T
O (+1) → P
Each letter is shifted forward by 1 position.

Following this consistent pattern, we apply a +1 alphabetical shift to each letter in IDC:
I (+1) → J
D (+1) → E
C (+1) → D

Combining the shifted letters, we get JED.