If in the given number “972569345”, the even digits are increased by two and the odd digits are decreased by one, then the digits are arranged in descending order from left to right, then what will be the product of the digits which are fifth from the left end and second from the right end?

The correct option is 24.

Step 1: Write down the original given number.
The given number is 972569345.

Step 2: Modify each digit according to the given conditions.
- If the digit is even, increase it by 2.
- If the digit is odd, decrease it by 1.

Let's process each digit from left to right:

- First digit is 9 (odd): 9 - 1 = 8
- Second digit is 7 (odd): 7 - 1 = 6
- Third digit is 2 (even): 2 + 2 = 4
- Fourth digit is 5 (odd): 5 - 1 = 4
- Fifth digit is 6 (even): 6 + 2 = 8
- Sixth digit is 9 (odd): 9 - 1 = 8
- Seventh digit is 3 (odd): 3 - 1 = 2
- Eighth digit is 4 (even): 4 + 2 = 6
- Ninth digit is 5 (odd): 5 - 1 = 4

The new sequence of digits is: 8, 6, 4, 4, 8, 8, 2, 6, 4.

Step 3: Arrange the modified digits in descending order (from left to right).
Sorting the digits from largest to smallest gives:
8, 8, 8, 6, 6, 4, 4, 4, 2

Step 4: Identify the required digits.
- The digit fifth from the left end is 6 (1st: 8, 2nd: 8, 3rd: 8, 4th: 6, 5th: 6).
- The digit second from the right end is 4 (1st from right: 2, 2nd from right: 4).

Step 5: Calculate the product of these two digits.

$\text{Product}=6\times 4=24$

Thus, the required product is 24.