If the 2^nd half of the letters of the word INTERMEDIATE are reversed and placed before 1^st half of the letters, which letter will be 2^nd to the right of 10^th letter from the right?

The correct option is D.

Let us break down the solution step-by-step:

Step 1: Analyze the original word
The given word is INTERMEDIATE.
Counting the letters in the word:
1: I, 2: N, 3: T, 4: E, 5: R, 6: M, 7: E, 8: D, 9: I, 10: A, 11: T, 12: E
The word contains a total of 12 letters.

Step 2: Divide the word into two halves
Since there are 12 letters, each half will contain 6 letters:
- 1^st half: I N T E R M
- 2^nd half: E D I A T E

Step 3: Reverse the 2^nd half and rearrange the letters
Reversing the 2^nd half (E D I A T E) gives: E T A I D E.
Now, placing this reversed 2^nd half before the 1^st half, we get the new sequence:
E T A I D E I N T E R M

Step 4: Find the required letter
We need to find the letter which is 2^nd to the right of the 10^th letter from the right.
In any sequence, going "right" from a position counted from the right means we subtract the positions:
Position from the right = 10 - 2 = 8^th letter from the right.
Let us count to the 8^th letter from the right in our new sequence (E T A I D E I N T E R M):
- 1^st from right: M
- 2^nd from right: R
- 3^rd from right: E
- 4^th from right: T
- 5^th from right: N
- 6^th from right: I
- 7^th from right: E
- 8^th from right: D

Thus, the letter is D.