If two cars start at the same point and move along a straight road, Car X at a constant speed of 40 km/h and Car Y at a constant speed of 60 km/h, which statement correctly compares their motions after 2 hours?

The correct option is Car Y will be 40 km ahead of Car X after 2 hours.

Step 1: Understand the given data

We are given the speeds of two cars moving along a straight road from the same starting point:
- Speed of Car X, $v_X=40\text{ km/h}$
- Speed of Car Y, $v_Y=60\text{ km/h}$
- Time elapsed, $t=2\text{ hours}$

Step 2: Calculate the distance traveled by Car X

Using the formula for distance covered at a constant speed, $\text{Distance}=\text{Speed}\times \text{Time}$:

$d_X=40\text{ km/h}\times 2\text{ hours}=80\text{ km}$

Step 3: Calculate the distance traveled by Car Y

Similarly, for Car Y:

$d_Y=60\text{ km/h}\times 2\text{ hours}=120\text{ km}$

Step 4: Compare their positions

To find how far ahead Car Y is from Car X, subtract the distance traveled by Car X from the distance traveled by Car Y:

$\text{Difference}=d_Y-d_X=120\text{ km}-80\text{ km}=40\text{ km}$

Therefore, after 2 hours, Car Y will be 40 km ahead of Car X.