Question Details

Find the value of 3 ÷ 3 × 2 6 ÷ 3 + 7 5 ÷ 5 × 6 ÷ 6 + 3 + 3 .

Options

A

1

B

6/7

C

8/7

D

2

Show Answer

Correct Answer :

Option A

1

Solution :

The correct answer is 1.

To find the value of the given expression, we evaluate the numerator and the denominator separately using the order of operations (BODMAS/PEMDAS rule), which dictates that we perform division and multiplication (from left to right) before addition and subtraction (from left to right).

Step 1: Simplify the Numerator

The expression in the numerator is:

3 ÷ 3 × 2 6 ÷ 3 + 7

First, perform the division operations from left to right:
3 ÷ 3 = 1
and
6 ÷ 3 = 2

Substitute these values back into the expression:
1 × 2 2 + 7

Next, perform the multiplication:
1 × 2 = 2

Substitute this back into the expression:
2 2 + 7

Now perform the addition and subtraction from left to right:
2 2 = 0
0 + 7 = 7

So, the numerator evaluates to 7.

Step 2: Simplify the Denominator

The expression in the denominator is:

5 ÷ 5 × 6 ÷ 6 + 3 + 3

First, perform the division operations from left to right:
5 ÷ 5 = 1

Now update the expression:
1 × 6 ÷ 6 + 3 + 3

Next, perform multiplication and division from left to right:
1 × 6 = 6
6 ÷ 6 = 1

Substitute this back into the expression:
1 + 3 + 3

Now perform the addition:
1 + 3 + 3 = 7

So, the denominator evaluates to 7.

Step 3: Calculate the Final Value

Substitute the simplified values of the numerator and the denominator back into the fraction:

7 7 = 1

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