In a certain code language;
“stay calm be ready” is coded as “ mn jk lm rs”
“ready for stay quiet” is coded as “ rp jk ut mn“
“calm nature for peace” is coded as” lm ve rp st”
“nature quiet for calm” is coded as “ ve ut rp lm”
If the code for the words “ready to for” is coded as “rpyzjk” then what will be code for “stay to”
Correct Answer :
mnyz
Solution :
The correct option is mnyz.
Let's break down the given statements step-by-step to decipher the code for each word:
1. "stay calm be ready" = “mn jk lm rs”
2. "ready for stay quiet" = “rp jk ut mn”
3. "calm nature for peace" = “lm ve rp st”
4. "nature quiet for calm" = “ve ut rp lm”
Step 1: Find the code for "stay" and "ready"
Comparing Statement 1 and Statement 2:
Common words: "stay", "ready"
Common codes: "mn", "jk"
So, {"stay", "ready"} are coded as {"mn", "jk"} in some order.
Step 2: Find the code for "calm"
Comparing Statement 1 and Statement 3 (or 4):
Common word: "calm"
Common code: "lm"
Therefore, the code for "calm" is "lm".
Step 3: Analyze the given condition
We are given that "ready to for" is coded as "rpyzjk" (or "rp", "yz", "jk").
Comparing Statement 3 and Statement 4:
Common words: "nature", "for", "calm"
Common codes: "ve", "rp", "lm"
Since "calm" = "lm", "nature" and "for" must correspond to "ve" and "rp".
From Statement 2 and Statement 3, the word "for" is present in both, and the common code is "rp".
Therefore, the code for "for" is "rp".
Now, in the phrase "ready to for" (coded as "rp", "yz", "jk"):
- We know "for" = "rp".
- From Step 1, {"stay", "ready"} = {"mn", "jk"}. Since "jk" is present in "rpyzjk", the code for "ready" must be "jk".
- Consequently, the code for "stay" must be "mn".
- The remaining word in "ready to for" is "to", and the remaining code is "yz". Thus, "to" = "yz".
Step 4: Find the code for "stay to"
- Code for "stay" = "mn"
- Code for "to" = "yz"
Combining these, the code for "stay to" is "mnyz".
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