In a row of 40 children, A is 13th from the left end and B is ninth from the right end. How many children are there between A and C if C is fourth to the left of B.

The correct option is 14.

Let us break down the positions of the children step-by-step to find the number of children between A and C.

Step 1: Determine the position of A.
The total number of children in the row is 40.
A is 13th from the left end.

Step 2: Determine the position of B.
B is 9th from the right end.

Step 3: Determine the position of C.
We are told that C is 4th to the left of B. Moving to the left of B means C is further away from the right end than B. Therefore, we add 4 to B's position from the right end:
Position of C from the right end = 9 + 4 = 13th from the right end.

Step 4: Find C's position from the left end.
To compare the positions of A and C directly, we convert C's position to be relative to the left end. We use the standard formula:
Total children = (Position from left) + (Position from right) - 1
$40=\text{Position of C from left}+13-1$
$40=\text{Position of C from left}+12$
$\text{Position of C from left}=40-12=28$
So, C is the 28th child from the left end.

Step 5: Calculate the number of children between A and C.
A is 13th from the left end, and C is 28th from the left end. The number of children strictly between them is given by:
Number of children = (Position of C from left) - (Position of A from left) - 1
$\text{Number of children}=28-13-1=14$
Thus, there are 14 children between A and C.