In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answers.

$\text{I. }{x}^2-7x-60=0$

$\text{II. }{y}^2+13y+40=0$

To find the relationship between $x$ and $y$, we need to solve both quadratic equations separately and compare their roots.

Step 1: Solve Equation (I)
The first equation is:
$x^2-7x-60=0$
We need to find two numbers that multiply to $-60$ and add up to $-7$. These numbers are $-12$ and $5$.
Factoring the quadratic equation:
$(x-12)(x+5)=0$
This gives the roots:
$x=12$ or $x=-5$

Step 2: Solve Equation (II)
The second equation is:
$y^2+13y+40=0$
We need to find two numbers that multiply to $40$ and add up to $13$. These numbers are $8$ and $5$.
Factoring the quadratic equation:
$(y+8)(y+5)=0$
This gives the roots:
$y=-8$ or $y=-5$

Step 3: Compare the values of x and y
Let us compare each value of $x$ with each value of $y$:
- Comparing $x=12$ with $y=-8$ and $y=-5$: In both cases, $12>-8$ and $12>-5$, so $x>y$.
- Comparing $x=-5$ with $y=-8$ and $y=-5$: We have $-5>-8$ (which means $x>y$) and $-5=-5$ (which means $x=y$).

Combining these observations, we conclude that $x\ge y$.