Question Details

In the first excited state of hydrogen atom, the energy of its electron is 10.2 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately: ____.

Options

A

2.1 × 10−11m

B

2.1 × 10−10m

C

2.1 × 10−9m

D

2.1 × 10−8m

Show Answer

Correct Answer :

Option B

2.1 × 10−10m

2.1 × 10⁻¹⁰ m

Solution :

In the hydrogen atom the Bohr model gives the radius of the electron orbit for a principal quantum number n as

r = n² a₀

where a₀ is the Bohr radius. Its measured value is

a₀ = 0.529 Å = 5.29 × 10⁻¹¹ m

The first excited state corresponds to the second energy level, so n = 2. Substituting into the radius formula:

r = (2)² a₀ = 4 a₀

r = 4 × 5.29 × 10⁻¹¹ m = 2.116 × 10⁻¹⁰ m

Rounding to two significant figures gives

r ≈ 2.1 × 10⁻¹⁰ m

Therefore the radial distance of the electron from the nucleus in the first excited state is approximately 2.1 × 10⁻¹⁰ m.

Unlock Our Free Library

Access expert-curated educational resources and study materials—completely free.

Discover more resources

You may also like

Mock Tests

View All
  • JEE
  • intermediate
  • 3 hours
  • chemistry, mathematics, physics
  • Proctored

  • JEE
  • intermediate
  • 3 hours
  • chemical engineering, mathematics, physics

Ask AI Tutor
5 left
Q1 View Question & Options
AI Tutor is solving this question...
Reading question context & options...