In the following reaction sequence, the major product Q is

The correct option is:

Step 1: Reduction of L-Glucose to n-hexane
When L-Glucose is prolonged heated with hydroiodic acid (HI and Δ), all hydroxyl groups and the carbonyl functional group undergo complete reduction to yield n-hexane:

${\text{C}}_6{\text{H}}_{12}{\text{O}}_6\underset{\text{Δ}}{\overset{\text{HI}}{\to }}{\text{CH}}_3-{\left({\text{CH}}_2\right)}_4-{\text{CH}}_3$

Step 2: Aromatization to form Benzene (Product P)
When n-hexane is heated with chromium oxide catalyst (${\text{Cr}}_2{\text{O}}_3$) at high temperature (775 K) and high pressure (10–20 atm), it undergoes dehydrogenation and cyclization (aromatization) to form benzene (${\text{C}}_6{\text{H}}_6$). Thus, intermediate P is Benzene.

Step 3: Free-radical addition reaction to form Product Q
When benzene reacts with excess chlorine (${\text{Cl}}_2$) under ultraviolet light (UV) in the absence of a Lewis acid catalyst (like anhydrous ${\text{FeCl}}_3$), free-radical addition occurs across the aromatic double bonds instead of electrophilic substitution. Three molecules of chlorine add to benzene, forming Benzene Hexachloride (BHC), chemically known as 1,2,3,4,5,6-hexachlorocyclohexane (${\text{C}}_6{\text{H}}_6{\text{Cl}}_6$).

${\text{C}}_6{\text{H}}_6+3{\text{Cl}}_2\stackrel{\text{UV light}}{\to }{\text{C}}_6{\text{H}}_6{\text{Cl}}_6$

Therefore, the major final product Q is hexachlorocyclohexane, represented by the structure with a cyclohexane ring containing chlorine atoms bonded to all six carbon atoms.