In the given word “WORKSHOP” if the letters at even position when counts from the left are changed with its just preceding letter according to alphabetical series and the letters at odd position when counts from the left are changed with its just succeeding letter according to alphabetical series position then how many letters are repeated in the word thus formed?

The correct option is None.

Let us break down the problem step-by-step to determine the new word formed after following the given position-based letter transformations.

Step 1: Write down the original word and identify the position of each letter from left to right.
Original Word: W O R K S H O P
Position 1 (Odd): W
Position 2 (Even): O
Position 3 (Odd): R
Position 4 (Even): K
Position 5 (Odd): S
Position 6 (Even): H
Position 7 (Odd): O
Position 8 (Even): P

Step 2: Apply the transformation rules based on letter positions.
- Rule for Odd positions (1, 3, 5, 7): Change to the just succeeding letter (+1 in alphabetical order).
- Rule for Even positions (2, 4, 6, 8): Change to the just preceding letter (-1 in alphabetical order).

Let us perform the transformation for each letter:
1. 1^st letter (W - Odd): W + 1 = X
2. 2^nd letter (O - Even): O - 1 = N
3. 3^rd letter (R - Odd): R + 1 = S
4. 4^th letter (K - Even): K - 1 = J
5. 5^th letter (S - Odd): S + 1 = T
6. 6^th letter (H - Even): H - 1 = G
7. 7^th letter (O - Odd): O + 1 = P
8. 8^th letter (P - Even): P - 1 = O

Step 3: Combine the new letters to form the final word.
The new word formed is: X N S J T G P O

Step 4: Check for repeated letters in the new word.
Looking at the letters of X N S J T G P O, every letter appears exactly once. There are no repeated letters.

Hence, the number of letters repeated in the word thus formed is None.