Question Details

In the number ‘248375975’ , how many pairs of digits have the same number between them (both forward and backward direction) as in the number series?

Options

A

Four

B

Two

C

One

D

Three

E

More than four

Show Answer

Correct Answer :

Option E

More than four

Solution :

The correct option is More than four.

To find the pairs of digits in the given number ‘248375975’ that have as many digits between them as in the natural number series (both in forward and backward directions), let us analyze the positions of each digit and count the intervening steps step-by-step.

Let us write down the number and count forward from each digit to match with the counting sequence:

Number: 2 4 8 3 7 5 9 7 5

1. Forward Direction Checking:

• Starting from 2:
- 2 to 3 (2 → 4, 3 → 8, 4 → 3): Not matching.
- 2 to 4 (position 1 to 2): Digit is 4, but sequence count is 3.
- 2 to 5 (position 1 to 6): Digits in between are 4, 8, 3, 7. Count from 2 is 2-3-4-5-6-7. At position 6, we have the digit 5, but counting gives 7 (2 → 3, 4 → 4, 8 → 5, 3 → 6, 7 → 7, 5 → 8). Let's check precisely:
- Digit 2 is at index 1.
- Counting from 2: index 2 = 3, index 3 = 4, index 4 = 5, index 5 = 6, index 6 = 7, index 7 = 8, index 8 = 9 (which is digit 7 at index 8, but at index 7 digit is 9). Wait, index 7 has digit 9, and count from 2 gives 2, 3, 4, 5, 6, 7, 8, 9! Digit 9 is at 7th place (index 7). Distance between 2 and 9: digits in between are 4, 8, 3, 7, 5 (5 digits). In counting: 2, 3, 4, 5, 6, 7, 8, 9 (6 steps, so 5 numbers between 2 and 9).
- Pair 1: (2, 9) in forward direction (2, _, _, _, _, _, 9 -> 5 digits between them: 4, 8, 3, 7, 5).

• Starting from 4:
- Counting: 4 → 5 (at 8), 6 (at 3), 7 (at 7), 8 (at 5), 9 (at 9).
- Notice that 4 is at 2nd position, and 9 is at 7th position. Distance between them is 7-2=5 steps, meaning 4 digits between them (8, 3, 7, 5). In the standard series, numbers between 4 and 9 are 5, 6, 7, 8 (4 numbers).
- Pair 2: (4, 9) in forward direction.

• Starting from 3:
- 3 is at 4th position. Counting forward: 3 → 4 (at 7), 5 (at 5).
- 3 is at 4th position, 5 is at 6th position. Distance = 6-4=2 steps, so 1 digit between them (7). In standard series: 3, 4, 5 (1 number between 3 and 5).
- Pair 3: (3, 5) at index 6 in forward direction.
- Continuing count from 3: 6 (at 9), 7 (at 7). 3 is at 4th position and 7 is at 8th position. Distance = 8-4=4 steps, so 3 digits between them (7, 5, 9). In standard series: 3, 4, 5, 6, 7 (3 numbers between 3 and 7).
- Pair 4: (3, 7) at index 8 in forward direction.

• Starting from 5 (at 6th position):
- Counting forward: 5 → 6 (at 9), 7 (at 7).
- 5 is at 6th position and 7 is at 8th position. Distance = 8-6=2 steps (1 digit between them: 9). In standard series: 5, 6, 7 (1 number between 5 and 7).
- Pair 5: (5, 7) at index 8 in forward direction.

2. Backward Direction Checking:

• Starting from 5 (at last position, index 9):
- Counting backward (towards left): 5 → 6 (at 7), 7 (at 9), 8 (at 5), 9 (at 7).
- Let's check 5 at index 9 to 7 at index 8: 1 step, no digits between them. In series: 5 to 7 has 1 digit.
- Let's check 5 at index 6 counting backward: 5 → 6 (at 3), 7 (at 8), 8 (at 4).
- Let's check 7 at index 8 counting backward: 7 → 8 (at 9), 9 (at 5 - index 6).
- 7 is at index 8 and 9 is at index 7: 1 step.
- Let's check 3 at index 4 counting backward: 3 → 4 (at 8).
- Let's check 5 at index 9 to 7 at index 5: index 9 to index 5 is 4 steps (3 digits in between: 7, 9, 5). In series, 5 to 7 has 1 digit (5, 6, 7).
- Let's check 7 at index 8 to 8 at index 3: index 8 to index 3 is 5 steps (4 digits in between: 9, 5, 7, 3). In series, between 7 and 8 there are 0 digits.
- Let's check 5 at index 9 to 8 at index 3: index 9 to index 3 is 6 steps (5 digits in between). In series, between 5 and 8 there are 2 digits (6, 7).
- Let's check 7 at index 5 counting backward: 7 → 8 (at 3), 9 (at 8 - index 3). 7 at index 5 and 9 at index 3: distance = 5-3=2 steps (1 digit between them: 3). In standard series: 7, 8, 9 (1 number between 7 and 9).
- Pair 6: (7, 9) from index 5 to index 3 in backward direction.

Since we have already found 6 valid pairs—(2, 9), (4, 9), (3, 5), (3, 7), (5, 7), and (7, 9)—the total number of pairs is greater than four.

Thus, the correct answer is More than four.

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