In the word ‘CREATION’, how many pairs of the letters have the same letters between them (both forward and backward direction) as in the English alphabet?
Correct Answer :
Two
Solution :
To find the pairs of letters in the word CREATION that have the same number of letters between them as in the English alphabet, we can analyze the word in both the forward (left-to-right) and backward (right-to-left) directions.
First, let's write down the letters of the word CREATION along with their positions in the word:
1: C
2: R
3: E
4: A
5: T
6: I
7: O
8: N
Now, let's list the alphabetical positions (A = 1, B = 2, C = 3, etc.) for each letter in the word to make comparison easy:
C = 3
R = 18
E = 5
A = 1
T = 20
I = 9
O = 15
N = 14
1. Forward Direction Search (Left-to-Right):
We count forward from each letter to see if we land on a letter that matches the alphabetical sequence:
- From C (position 1): count D, E, F, G, H, I, J. No match.
- From R (position 2): count S, T, U, V, W, X. No match.
- From E (position 3): count F, G, H, I, J. No match.
- From A (position 4): count B, C, D, E. No match.
- From T (position 5): count U, V, W. No match.
- From I (position 6): count J, K. No match.
- From O (position 7): count P. No match.
There are no such pairs in the forward direction.
2. Backward Direction Search (Right-to-Left):
We count forward from each letter starting from the right side of the word:
- From N (position 8): count O, P, Q, R, S, T, U. The letter O is adjacent to N in the word (position 7), which matches the alphabetical order (N, O). This gives us our first pair: (N, O).
- From O (position 7): count P, Q, R, S, T, U. No match.
- From I (position 6): count J, K, L, M, N. No match.
- From T (position 5): count U, V, W, X. No match.
- From A (position 4): count B, C, D. No match.
- From E (position 3): count F, G. The letter R is at position 2, and C is at position 1. E to C has one letter between them in the word (R), and in the alphabet, there is also exactly one letter between C and E (D). Counting from E: F, G. Counting from C: D, E. Thus, the pair (C, E) has the same number of letters between them. Let's verify: in C_E, there is 1 letter (D). In CR_E, there is 1 letter (R). This is our second pair: (C, E).
- From R (position 2): count S. No match.
Thus, we find exactly two pairs of letters that satisfy the condition: (N, O) and (C, E).
Therefore, the number of such pairs is Two.
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