In the word ‘CREATION’, how many pairs of the letters have the same letters between them (both forward and backward direction) as in the English alphabet?

The correct option is Two.

To find the number of pairs of letters in the word "CREATION" that have the same number of letters between them as in the English alphabet (in both forward and backward directions), we can analyze the positions and alphabetical order of the letters.

Let us write down the English alphabetical positions for each letter in the word "CREATION":
C = 3
R = 18
E = 5
A = 1
T = 20
I = 9
O = 15
N = 14

We need to find pairs of letters $L_1$ and $L_2$ at positions $p_1$ and $p_2$ in the word such that the absolute difference in their word positions equals the absolute difference in their alphabetical positions:
$|p_1-p_2|=|\text{Alphabetical Position of}{L}_1-\text{Alphabetical Position of}{L}_2|$

Let's check the letter pairs step-by-step:

1. Checking in the Forward Direction:
• From C (position 1, value 3): We count forward in alphabetical order: D (at position 2), E (at position 3). Since E is at position 3 in the word, this is a match. The pair is (C, E).
• From R (position 2, value 18): Counting forward: S (3), T (4), U (5)... no matches.
• From E (position 3, value 5): Counting forward: F (4), G (5), H (6), I (7)... no matches.
• From A (position 4, value 1): Counting forward: B (5), C (6), D (7)... no matches.
• From T (position 5, value 20): Counting forward: U (6), V (7)... no matches.
• From I (position 6, value 9): Counting forward: J (7), K (8)... no matches.
• From O (position 7, value 15): Counting forward: P (8)... no matches.

2. Checking in the Backward Direction:
• From N (position 8, value 14): We count backward toward the beginning of the word: O (position 7, value 15). Since N and O are adjacent in the alphabet, and they are adjacent here, this is a match. The pair is (N, O).
• Checking other letters backward does not yield any further matches.

Thus, there are exactly two such pairs: (C, E) and (N, O).