In these questions, the relationship between different elements is shown in the statements. The statements are followed by two conclusions.

$\text{Statements:}$

$D\ge K<H=0;N>J\ge H;P\ge K<Y$

$\text{Conclusions:}$

$\text{I.}N>K$

$\text{II.}P<D$

The correct answer is If only conclusion I is true.

Given Statements:
1. $D\ge K<H=0$
2. $N>J\ge H$
3. $P\ge K<Y$

Let us evaluate each conclusion step-by-step:

Evaluating Conclusion I: $N>K$
From Statement 2, we have: $N>J\ge H$, which implies $N>H$.
From Statement 1, we have: $K<H$, which is equivalent to $H>K$.
Combining these relations through element $H$ gives: $N>H>K$.
Therefore, $N>K$ is definitely true.
Thus, Conclusion I is true.

Evaluating Conclusion II: $P<D$
From Statement 1, we have: $D\ge K$.
From Statement 3, we have: $P\ge K$.
Here, both $D$ and $P$ are greater than or equal to $K$. Since there is no direct inequality relation established between $P$ and $D$ (the comparison signs point away from each other at $K$), no definitive relationship between $P$ and $D$ can be determined.
Thus, Conclusion II is false.

Hence, only conclusion I follows.