In this question, a group of number/symbol is coded using letter codes as per the codes given below and the conditions which follow. The correct combination of codes following the conditions is your answer. If none of the conditions follow, then codes for the respective Number/Symbol to be followed directly as given in the table.
| Number/symbol | 2 | @ | 9 | 5 | $ | 3 | & | % | # | 7 | + | 4 | 8 | 6 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Code | P | T | L | J | A | W | E | Q | D | R | S | B | U | F |
Conditions –
If the first element is a number and the last a symbol, the codes for these two (the first and the last elements) are to be interchanged.
If the first element is an odd number and the last an even number, the first and last elements are to be coded as
If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
What will be the code for the following group of number-symbol? 537+
Correct Answer :
SWRJ
Solution :
The correct answer is SWRJ.
Step 1: Identify the direct code for each element from the given table:
• 5 is coded as J
• 3 is coded as W
• 7 is coded as R
• + is coded as S
Without applying any conditions, the direct code would be JWRS.
Step 2: Evaluate the given conditions:
• Condition 1: "If the first element is a number and the last a symbol, the codes for these two (the first and the last elements) are to be interchanged."
- In 537+, the first element (5) is a number and the last element (+) is a symbol.
- Therefore, Condition 1 applies.
• Condition 2 & 3: Do not apply to this group.
Step 3: Apply Condition 1 to find the final combination:
• Swap the codes of the 1st element (5) and the 4th element (+):
- 1st position gets the code for +, which is S.
- 4th position gets the code for 5, which is J.
• The middle elements (3 and 7) retain their original codes (W and R).
Thus, the final coded combination for 537+ is SWRJ.
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