John takes twice as much time as Jack to finish a job. Jack and Jim together take one-thirds of the time to finish the job than John takes working alone. Moreover, in order to finish the job, John takes three days more than that taken by three of them working together. In how many days will Jim finish the job working alone?
Correct Answer :
Solution :
The correct answer is 4 days. Let's build the solution step-by-step from the given conditions.
Step 1: Assign a variable and establish John's time
Let Jack take x days to finish the job alone.
Since John takes twice as much time as Jack:
John's time = 2x days
Step 2: Find Jack and Jim's combined time
Jack and Jim together take one-third of the time John takes alone:
Step 3: Find Jim's individual rate (and time)
Their combined rate (work done per day) is:
Jack's individual rate:
Jim's rate = (Jack + Jim)'s combined rate − Jack's rate:
So Jim alone takes 2x days to finish the job.
Step 4: Find all three working together
Combined rate of John + Jack + Jim:
Time for all three together:
Step 5: Apply the final condition — "John takes 3 more days than all three together"
Step 6: Find Jim's time
We established that Jim takes 2x days alone. Substituting x = 2:
Verification Summary:
• Jack = 2 days | John = 4 days | Jim = 4 days
• Jack + Jim together = 1 day (rate = ½ + ¼ = ¾ → time = 4/3 days) — wait, let's verify: rate of Jack(1/2) + Jim(1/4) = 3/4 → time = 4/3 days = (1/3) × 4 ✔
• All three rate = 1/4 + 1/2 + 1/4 = 1 → time = 1 day
• John (4 days) − All three (1 day) = 3 days ✔
✅ Jim will finish the job working alone in 4 days.
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