Keeping the significant figures in view the sum of the physical quantities 52.0 m, 153.2 m and 0.123 m is

The correct answer is 205.3 m.

Step-by-step Explanation:

Step 1: Perform the standard addition of the given quantities.

We need to find the sum of the three physical quantities: 52.0 m, 153.2 m, and 0.123 m.

$\text{Sum}=52.0+153.2+0.123=205.323\text{m}$

Step 2: Apply the rules of significant figures for addition.

When adding measured physical quantities, the final result must be rounded off to the same number of decimal places as the quantity having the least number of decimal places.

Let's check the number of decimal places for each value:

• 52.0 m has 1 decimal place.
• 153.2 m has 1 decimal place.
• 0.123 m has 3 decimal places.

The minimum number of decimal places among the given quantities is 1 decimal place (from 52.0 m and 153.2 m).

Step 3: Round off the result.

Rounding 205.323 m to 1 decimal place gives 205.3 m (since the digit after 3 is 2, which is less than 5, we drop the remaining digits without changing 3).

Thus, keeping significant figures in view, the correct sum is 205.3 m.