Question Details

Let a, b, x, y be real numbers such that a2+b2=25, x2+y2=169, and ax+by=65. If k=ay-bx, then

Options

A

k = 0

B

k>0

C

k=513

D

k=-513

Show Answer

Correct Answer :

Option A

k = 0

Solution :

We are given the following relations:
a2+b2=25
x2+y2=169

Now let's multiply these two equations:
(a2+b2)(x2+y2)=25×169
a2x2+a2y2+b2x2+b2y2=4225

We can rewrite the left-hand side using the algebraic identity:
(ax+by)2+(ay-bx)2=a2x2+2abxy+b2y2+a2y2-2abxy+b2x2
=a2x2+a2y2+b2x2+b2y2

Thus:
(ax+by)2+(ay-bx)2=(a2+b2)(x2+y2)

Substitute the given values into the identity:
652+k2=25×169
4225+k2=4225
k2=0
k=0

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