Let AX = B be a system of three linear equations in three variables. Then the system has
(A) a unique solution if —A— = 0
(B) a unique solution if —A— ̸= 0
(C) no solutions if —A— = 0 and (adj A) B ̸= 0
(D) infinitely many solutions if —A— = 0 and (adj A)B = 0
Choose the correct answer from the options given below:
Correct Answer :
(B), (C) and (D) only
Solution :
The correct answer is (B), (C) and (D) only.
Explanation:
Consider a system of three linear equations in three variables written in matrix form as:
where is the coefficient matrix of order , is the column matrix of variables, and is the column matrix of constant terms. The determinant of is represented as (or in the question statement).
Let's analyze the conditions step-by-step:
1. Unique Solution Condition ():
If the determinant of the coefficient matrix is non-zero (), then is a non-singular matrix. Consequently, the inverse matrix exists.
We can multiply both sides of the matrix equation by :
Using the associative property of matrix multiplication:
Since (where is the identity matrix):
This provides a single, unique solution for the system of equations. Thus, statement (B) is correct, and statement (A) is incorrect.
2. Singular Matrix Conditions ():
If the determinant of the coefficient matrix is zero (), the matrix is singular and the inverse does not exist. In this case, we determine the consistency of the system by calculating the product of the adjoint matrix of and the constant matrix , represented as :
Consequently, statements (B), (C), and (D) are all correct, making the choice (B), (C) and (D) only the correct answer.
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