Question Details

Let both p and k be prime numbers such that (p2 + k) is also a prime number less than 30. What is the number of possible values of k?

Options

A

4

B

5

C

6

D

7

Show Answer

Correct Answer :

Option B

5

Solution :

The correct option is 5 (which corresponds to Option 5 in the list of choices).


Step 1: Understand the given condition

We are given that p and k are both prime numbers.

We are told that p2+k is also a prime number, and this prime number must be strictly less than 30.


Step 2: Determine possible values for p

Since p and k are prime numbers, the smallest prime number is 2.

If p5, then p225. Since k2, p2+k27. Let's check candidate values of p:

1. If p=2:
p2=4
We need 4+k to be a prime number less than 30, where k is a prime number.
Let's check possible prime values for k:
- If k=3: 4+3=7 (Prime < 30) ⇒ Valid! (k=3)
- If k=7: 4+7=11 (Prime < 30) ⇒ Valid! (k=7)
- If k=9 (Not prime)
- If k=13: 4+13=17 (Prime < 30) ⇒ Valid! (k=13)
- If k=19: 4+19=23 (Prime < 30) ⇒ Valid! (k=19)
- If k=23: 4+23=27 (Not prime, 27=3×9)
- Other primes for k like 2, 5, 11, 17: 4+2=6 (even), 4+5=9 (not prime), 4+11=15 (not prime), 4+17=21 (not prime).


2. If p=3:
p2=9
We need 9+k to be a prime number less than 30, where k is prime.
- If k=2: 9+2=11 (Prime < 30) ⇒ Valid! (k=2)
- If k=4 (Not prime)
- If k=8 (Not prime)
- If k=10 (Not prime)
- For any odd prime k, 9+k will be even and greater than 2, hence composite. So only k=2 works when p=3.


3. If p=5:
p2=25
We need 25+k<30, so k<5.
- If k=2: 25+2=27 (Not prime)
- If k=3: 25+3=28 (Not prime)


4. If p7:
p249, which already exceeds 30.


Step 3: Collect all unique valid values of k

The unique prime values of k that satisfy the condition are:

k{2,3,7,13,19}


Counting the total number of valid values of k, we get exactly 5 values.


Thus, the number of possible values of k is 5.

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