Let C be a circle of radius 5 meters having center at O. Let PQ be a chord of C that passes through points A and B where A is located 4 meters north of O and B is located 3 meters east of O. Then, the length of PQ, in meters, is nearest to
Correct Answer :
8.8
Solution :
The correct option is 8.8.
To find the length of the chord , we can use a Cartesian coordinate system where the center of the circle is placed at the origin .
Step 1: Write the equation of the circle.
Since the circle has its center at and a radius of meters, its equation is:
Step 2: Determine the coordinates of points A and B.
- Point is located 4 meters north of , which corresponds to the positive y-axis: .
- Point is located 3 meters east of , which corresponds to the positive x-axis: .
Step 3: Find the equation of the line passing through A and B.
The line passing through and represents the line containing the chord .
Using the intercept form of a linear equation, we get:
Multiplying the entire equation by 12 to clear the denominators gives:
Step 4: Calculate the perpendicular distance from the center O to the line.
The perpendicular distance from the origin to the line is given by the formula:
Simplifying this expression yields:
Step 5: Determine the length of the chord PQ.
The length of a chord in a circle of radius at a perpendicular distance from the center is:
Substituting and into the formula:
Estimating :
Rounding to the nearest option, the length of the chord is nearest to 8.8.
Access expert-curated educational resources and study materials—completely free.
Create, conduct, and manage professional online assessments with Mindyard. Perfect for teachers and institutes.
Copyright © 2026 Mindyard. All Rights Reserved.