Question Details

Let G(V,E) be a simple, undirected graph. A vertex cover of G is a subset V′ ⊆ V such that for every (u,v) ∈ E, u ∈ V′ or v ∈ V′. Let the size of the smallest vertex cover in G be k. Let S be any vertex cover of size k. For a vertex v ∈ V, which of the following constraints will always ensure that v ∈ S?

Options

A

The degree of v is at least k +1

B

The vertex v is on a path of length k +1

C

The vertex v is on a cycle of length k +1

D

The vertex v is a part of a clique of size k

Show Answer

Correct Answer :

Option A

The degree of v is at least k +1

Solution :

The correct option is: The degree of v is at least k + 1.

Let us understand why this constraint always ensures that the vertex v must be in any vertex cover S of the minimum size k.

By definition, a vertex cover S of a graph G=(V,E) is a subset of vertices such that every edge in the graph has at least one of its endpoints in S.
Here, we are given that the size of the smallest vertex cover is k, and S is any vertex cover of size k, so |S|=k.

Let the degree of a vertex v be denoted by deg(v). The degree of v is the number of edges incident to v.
Suppose that deg(v)k+1. This means there are at least k+1 distinct edges incident to v, say (v,u1),(v,u2),...,(v,ud) where dk+1 and u1,u2,...,ud are distinct neighbors of v.

We want to prove that v must belong to S. Let us prove this by contradiction.
Assume for contradiction that vS.

Since S is a valid vertex cover, it must cover all the edges incident to v. That is, for every edge (v,ui) for i=1,2,...,d, at least one endpoint of the edge must be in S.
Because we assumed vS, the other endpoint ui must be in S for every i=1,2,...,d to cover each of these incident edges.

Therefore, we must have:
{u1,u2,...,ud}S
Since all ui are distinct, the size of the vertex cover S must satisfy:
|S|d
Substituting dk+1, we get:
|S|k+1
But this contradicts our initial fact that the size of S is k (|S|=k).

Since the assumption vS leads to a contradiction, the vertex v must be in S.
Thus, if the degree of v is at least k+1, v is guaranteed to be in any vertex cover of size k.

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