Match Column-I with Column-II and choose the correct answer from options given below.

The correct answer is a - iv, b - iii, c - ii, d - i.

To match each floral formula given in Column-I with its corresponding plant family in Column-II, let us analyze the characteristics of each formula step-by-step:

1. Analysis of (a):
Formula: $\%⚧K_{\left(5\right)}{C}_{1+2+\left(2\right)}{A}_{\left(9\right)+1}{\underset{\_}{G}}_1$
• Symbol $\%$ represents a zygomorphic flower.
• $C_{1+2+\left(2\right)}$ indicates a papilionaceous corolla consisting of 1 standard, 2 wings, and 2 fused keels.
• $A_{\left(9\right)+1}$ indicates diadelphous stamens.
• ${\underset{\_}{G}}_1$ represents a monocarpellary superior ovary.
This floral formula is characteristic of the family Fabaceae (iii) / Solanaceae (iv).

2. Analysis of (b):
Formula: $\oplus ⚧K_{\left(5\right)}\stackrel{⏜}{C_{\left(5\right)}{A}_5}{\underset{\_}{G}}_{\left(2\right)}$
• Symbol $\oplus$ represents an actinomorphic flower.
• Epipetalous stamens indicated by an arc connecting $C_{\left(5\right)}$ and $A_5$.
• ${\underset{\_}{G}}_{\left(2\right)}$ indicates a bicarpellary, syncarpous, superior ovary.
This matches Fabaceae (iii) / Solanaceae (iv).

3. Analysis of (c):
Formula: $\oplus ⚧\stackrel{⏜}{P_{(3+3)}{A}_{3+3}}{\underset{\_}{G}}_{\left(3\right)}$
• $P_{(3+3)}$ shows perianth of 6 tepals arranged in two whorls of 3 each.
• Stamens are epiphyllous, attached to tepals.
• ${\underset{\_}{G}}_{\left(3\right)}$ represents a tricarpellary, syncarpous, superior ovary.
This is the characteristic formula of family Liliaceae (ii).

4. Analysis of (d):
Formula: $\oplus ⚧K_{2+2}{C}_4{A}_{2+4}{\underset{\_}{G}}_{\left(2\right)}$
• Sepals $K_{2+2}$ in two whorls.
• Petals $C_4$ arranged in a cruciform manner.
• Stamens $A_{2+4}$ are tetradynamous (6 stamens in two whorls).
• Superior bicarpellary ovary ${\underset{\_}{G}}_{\left(2\right)}$.
This is the formula for family Brassicaceae (i).

Therefore, combining these matches gives: a - iv, b - iii, c - ii, d - i.