Question Details

Match List - I with List - II.

(a)  (i) Hell-Volhard-Zelinsky
reaction
(b)  (ii) Gattermann-Koch
reaction
(c)  (iii) Haloform reaction
(d)  (iv) Esterification

Choose the correct answer from the options given below.

Options

A

(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

B

(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)

C

(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)

D

(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

Show Answer

Correct Answer :

Option D

(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

Solution :

The correct answer is: (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

Let us analyze each reaction shown in the images and match it with the correct named reaction from List-II.

Reaction (a): The image shows benzene reacting with CO, HCl in the presence of Anhydrous AlCl3/CuCl.

This is a classic formylation reaction where carbon monoxide and HCl act as the formylating agent, with anhydrous AlCl3 (a Lewis acid catalyst) and CuCl as co-catalyst, to introduce an aldehyde group (−CHO) onto the benzene ring, producing benzaldehyde.

This is the Gattermann-Koch reaction — a method for preparing aromatic aldehydes by treating an aromatic compound with CO and HCl in the presence of AlCl3 and CuCl.

(a) → (ii) Gattermann-Koch reaction

Reaction (b): The image shows a compound with the structure R−CO−CH3 (a methyl ketone) reacting with NaOX (sodium hypohalite, where X = Cl, Br, or I).

When a methyl ketone (R−COCH3) is treated with a sodium hypohalite (NaOX), the methyl group adjacent to the carbonyl is trihalogenated, and the resulting trihalomethyl group (CX3) is cleaved off as a haloform (CHX3), leaving behind a carboxylate salt (RCOONa).

This is the Haloform reaction — a well-known reaction specific to methyl ketones and secondary alcohols of the type CH3−CH(OH)−R.

(b) → (iii) Haloform reaction

Reaction (c): The image shows R−CH2−OH (a primary alcohol) reacting with R'COOH (a carboxylic acid) in the presence of Conc. H2SO4.

When an alcohol reacts with a carboxylic acid in the presence of concentrated sulphuric acid (which acts as a dehydrating agent and catalyst), an ester is formed along with water. This is a condensation reaction:

R−CH2−OH + R'COOH H2SO4 R'COOCH2R + H2O

This is the Esterification reaction — specifically Fischer esterification, where an acid and an alcohol combine to form an ester.

(c) → (iv) Esterification

Reaction (d): The image shows R−CH2−COOH (a carboxylic acid with an α-hydrogen) reacting with (i) X2/Red P (halogen with red phosphorus) followed by (ii) H2O (hydrolysis).

When a carboxylic acid having an α-hydrogen is treated with a halogen (Cl2 or Br2) in the presence of red phosphorus (which generates the phosphorus trihalide PX3 in situ), halogenation occurs specifically at the α-carbon. The red phosphorus first converts the acid to an acyl halide, which then undergoes α-halogenation. Subsequent hydrolysis gives the α-halo carboxylic acid.

R−CH2−COOH → R−CHX−COOH

This is the Hell-Volhard-Zelinsky (HVZ) reaction — a reaction used for α-halogenation of carboxylic acids using Cl2 or Br2 in the presence of red phosphorus (or PBr3).

(d) → (i) Hell-Volhard-Zelinsky reaction

Final Matching:
(a) ��� (ii) Gattermann-Koch reaction
(b) → (iii) Haloform reaction
(c) → (iv) Esterification
(d) → (i) Hell-Volhard-Zelinsky reaction

This corresponds to option: (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i).

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