Match List-I with List-II
| List-I (Linguistic family) | List-II (Branch/Group) |
|---|---|
| (A) Indo-European (Aryan) | (I) Iranian |
| (B) Sino-Tibetan (Kirata) | (II) Munda |
| (C) Austric (Nishada) | (III) North Assam |
| (D) Dravidian (Dravida) | (IV) North Dravidian |
Choose the correct answer from the options given below:
Correct Answer :
(A) - (I), (B) - (III), (C) - (II), (D) - (IV)
Solution :
The correct option is (A) - (I), (B) - (III), (C) - (II), (D) - (IV).
Let us analyze the linguistic families and their corresponding branches/groups to understand why this mapping is correct:
1. (A) Indo-European (Aryan) → (I) Iranian
The Indo-European language family is one of the largest language families in the world. It includes the Indo-Iranian branch, which is further subdivided into the Indo-Aryan, Iranian, and Nuristani groups. Therefore, Iranian is a branch of the Indo-European family, matching (A) with (I).
2. (B) Sino-Tibetan (Kirata) → (III) North Assam
The Sino-Tibetan language family (traditionally referred to as Kirata in the Indian context) comprises languages spoken in East Asia, Southeast Asia, and parts of South Asia. The Tibeto-Burman branch of this family includes the North Assam group of languages (such as Mising, Adi, Nishi, etc.), matching (B) with (III).
3. (C) Austric (Nishada) → (II) Munda
The Austric language family (traditionally associated with Nishada) in India is primarily represented by the Austroasiatic languages. This family is divided into two main branches: Mon-Khmer and Munda. The Munda languages (like Santhali, Mundari, Ho) are spoken mainly in eastern and central India, matching (C) with (II).
4. (D) Dravidian (Dravida) → (IV) North Dravidian
The Dravidian language family is spoken predominantly in South India and parts of eastern and central India. It is structurally classified into Northern, Central, South-Central, and Southern groups. Thus, North Dravidian (which includes languages like Kurukh and Malto) is a direct branch of the Dravidian family, matching (D) with (IV).
Combining these individual matches, we get:
(A) → (I)
(B) → (III)
(C) → (II)
(D) → (IV)
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