Question Details

Match List I with List II

List I

List II

ARNA polymerase IIIIsnRNPs
BTermination of transcriptionIIPromotor
CSplicing of ExonsIIIRho factor
DTATA boxIVSnRNAs, tRNA

Choose the correct answer from the options given below :

Options

A

A-II, B-IV, C-I, D-III

B

A-III, B-II, C-IV, D-I

C

A-III, B-IV, C-I, D-II

D

A-IV, B-III, C-I, D-II

Show Answer

Correct Answer :

Option D

A-IV, B-III, C-I, D-II

A-IV, B-III, C-I, D-II

Solution :

To find the correct match, let us analyze each item in List I with its corresponding match in List II:

A. RNA polymerase III: In eukaryotes, RNA polymerase III is the enzyme responsible for transcribing transfer RNA (tRNA), 5S ribosomal RNA (5S rRNA), and some small nuclear RNAs (snRNAs, such as U6 snRNA). Therefore, A matches with IV (SnRNAs, tRNA).

B. Termination of transcription: In prokaryotic cells, transcription termination can be Rho-dependent, requiring a specific termination protein called the Rho factor (a helicase) to dissociate the RNA transcript from the DNA template. Therefore, B matches with III (Rho factor).

C. Splicing of Exons: Splicing is the post-transcriptional modification process in eukaryotic cells where non-coding introns are removed and coding exons are joined. This reaction is catalyzed by a large molecular complex called the spliceosome, which is made up of small nuclear ribonucleoproteins, commonly referred to as snRNPs ("snurps"). Therefore, C matches with I (snRNPs).

D. TATA box: The TATA box is a conserved, adenine- and thymine-rich DNA sequence found in the promoter region of eukaryotic genes. It acts as a key site for transcription factor binding to initiate the assembly of the transcription machinery. Therefore, D matches with II (Promoter).

Combining all the correct matches, we get:
A - IV
B - III
C - I
D - II

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