Question Details

Nine persons – A, B, C, D, E, F, G, H, and I – are sitting around a circular table, all facing towards the center. But not necessarily in the same order.

Only one person sits between A and F. C sits third to the right B, who is an immediate neighbor of A. Only three people sit between A and G. G sits second to the left of H. I is an immediate neighbor of both A and H. F is not an immediate neighbor of D.

Four of the following five are alike in a certain way and thus form a group. Find the one which doesn’t belong to the group.

Options

A

B-E

B

F-C

C

C-D

D

D-I

E

H-B

Show Answer

Correct Answer :

Option E

H-B

H-B

Solution :

To find the odd one out, let us first determine the seating arrangement of the nine persons (A, B, C, D, E, F, G, H, and I) sitting around a circular table facing the center.

Let us analyze the clues step-by-step:
1. "Only three people sit between A and G."
In a circular table with 9 people, having 3 people between A and G means G can be either 4 positions to the left of A or 4 positions to the right of A.
Let us place A at position 1 (numbered 1 to 9 clockwise). Since there are 3 people between A and G, G must be at position 5 (going clockwise: 2, 3, 4 are the 3 people, so G is 5; or going counter-clockwise: 9, 8, 7 are the 3 people, so G is 6). Let's trace both possibilities.

2. "I is an immediate neighbor of both A and H."
Since I is adjacent to both A and H, the sequence must be either H-I-A or A-I-H. This means H and A are separated by exactly one person, who is I.

3. "G sits second to the left of H."
Since everyone faces the center, left is clockwise and right is counter-clockwise (or vice versa depending on orientation). Let's define clockwise as left and counter-clockwise as right.
If G is second to the left of H, then H sits second to the right of G.
If we place G at position 5 (with A at 1):
H, being 2 positions to the left of G (so G is 2 positions to the left of H, which means H is 2 positions to the right of G, i.e., counter-clockwise): H would be at position 3.
If H is at position 3, since I must be between A (at 1) and H (at 3), I must be at position 2. This fits perfectly!
Let us verify the other direction. If G was at position 6 (3 people between A at 1 and G at 6 going counter-clockwise: 9, 8, 7 are between them):
If G is second to the left of H, H is second to the right of G, so H would be at position 4. But then I cannot be adjacent to both A (at 1) and H (at 4) because they are not separated by exactly one position. Thus, our first case is correct:
- A is at position 1
- I is at position 2
- H is at position 3
- G is at position 5

4. "C sits third to the right of B, who is an immediate neighbor of A."
Since B is an immediate neighbor of A, and A's neighbor at position 2 is already occupied by I, B must be A's other neighbor at position 9.
Since C sits third to the right of B (counter-clockwise is right): starting from B at 9, the first to the right is A (1), second is I (2), and third is H (3). But position 3 is already occupied by H. This means "right" must refer to the clockwise direction in this orientation, or we need to reverse our direction mapping.
Let's define the directions consistently:
Let's place the positions 1 to 9 in clockwise order:
- A is at 1.
- Since "I is an immediate neighbor of both A and H", we have two options for the placement of H and I:
- Case A: I at 2, H at 3.
- Case B: I at 9, H at 8.
Let's test Case A (A at 1, I at 2, H at 3):
- "G sits second to the left of H." Since they face the center, left is clockwise. So second to the left of H (3) is 5. Thus, G is at 5. This matches our previous placement.
- "B is an immediate neighbor of A." The neighbors of A (1) are 2 and 9. Since 2 is occupied by I, B must be at 9.
- "C sits third to the right of B." Facing the center, right is counter-clockwise. From B (9), going counter-clockwise (decreasing numbers): 1st right is 8, 2nd right is 7, 3rd right is 6. So C is at 6.
- Let's check: "Only three people sit between A and G." A is at 1, G is at 5. Between them clockwise are 2, 3, 4 (3 people: I, H, and the person at 4). Between them counter-clockwise are 9, 8, 7, 6 (4 people). This satisfies the condition "Only three people sit between A and G" (in one of the directions).

5. "Only one person sits between A and F."
The positions adjacent to the neighbors of A are 3 and 8. Position 3 is occupied by H. So F must be at position 8 (one person, B at 9, sits between A at 1 and F at 8).

6. "F is not an immediate neighbor of D."
The remaining positions to fill are 4 and 7. The remaining people are D and E.
F is at 8, so its neighbors are 7 and 9 (B). Since F is not an immediate neighbor of D, D cannot be at 7. Thus, D must be at 4, and E must be at 7.

Let's write down the final circular arrangement (clockwise):
1 - A
2 - I
3 - H
4 - D
5 - G
6 - C
7 - E
8 - F
9 - B

Now let's examine the options to find the relationship between the pairs of letters:
- B-E: B is at 9, E is at 7. There is exactly 1 person (F at 8) sitting between them.
- F-C: F is at 8, C is at 6. There is exactly 1 person (E at 7) sitting between them.
- C-D: C is at 6, D is at 4. There is exactly 1 person (G at 5) sitting between them.
- D-I: D is at 4, I is at 2. There is exactly 1 person (H at 3) sitting between them.
- H-B: H is at 3, B is at 9. There are 3 people between them in one direction (I, A, B is not possible, let's see: 4, 5, 6, 7, 8 are between 3 and 9; and 2, 1, 9: between 3 and 9 clockwise are 4, 5, 6, 7, 8 (5 people) and counter-clockwise are 2, 1 (2 people)). Therefore, H and B do not have exactly 1 person sitting between them.

In all the first four pairs, the two persons have exactly one person sitting between them. H-B is the only pair that does not follow this pattern.

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