One non-zero digit, one vowel and one consonant from English alphabet (in capital) are to be used in forming passwords, such that each password has to start with a vowel and end with a consonant. How many such passwords can be generated?

The correct option is 945.

To find the total number of passwords that can be generated, we can break down the choices for each position of the password step-by-step:

Step 1: Understand the structure of the password
Each password must contain exactly one vowel, one non-zero digit, and one consonant. Since the password must start with a vowel and end with a consonant, the only possible arrangement for the three characters is:
[Vowel] [Digit] [Consonant]

Step 2: Determine the number of options for each position
1. Vowels: The English alphabet has 5 vowels (A, E, I, O, U). Therefore, there are 5 choices for the first position.
2. Non-zero digits: The non-zero digits are 1, 2, 3, 4, 5, 6, 7, 8, and 9. Therefore, there are 9 choices for the middle position.
3. Consonants: Out of 26 letters in the English alphabet, 5 are vowels, which leaves 21 consonants. Therefore, there are 21 choices for the last position.

Step 3: Calculate the total number of passwords
Using the fundamental counting principle, the total number of unique passwords is the product of the number of choices for each position:

$$\text{Total Passwords}=5\times 9\times 21$$

Multiplying these values together:
5 × 9 = 45
45 × 21 = 945

Thus, 945 unique passwords can be generated.