Question Details

Phosphoric acid ionizes in three steps with their ionization constant values Ka1,Ka2,Ka3, respectively, while K is the overall ionization constant. Which of the following statements are true?


A. log K = log Ka1 + logKa2 + logKa3

B. H3PO4 is a stronger acid than  H2PO4- and HPO2-4

C. Ka1 > Ka2 > Ka3

D.  Ka1 = Ka3 + Ka2/2


Choose the correct answer from the options given below :

Options

A

A, B and C only

B

A and B only

C

A and C only

D

B, C and D only

Show Answer

Correct Answer :

Option A

A, B and C only

A, B and C only

Solution :

**Statement A:** The overall ionization constant K for phosphoric acid is the product of the three stepwise constants:

K = Ka1·Ka2·Ka3

Taking the base‑10 logarithm of both sides gives

log K = log Ka1 + log Ka2 + log Ka3

Hence statement A is true.


**Statement B:** The first dissociation of phosphoric acid is

H₃PO₄ ⇌ H₂PO₄⁻ + H⁺  Ka1

Since Ka1 (≈ 7.5 × 10⁻³) is larger than Ka2 and Ka3, the parent acid H₃PO₄ donates a proton more readily than its conjugate bases H₂PO₄⁻ and HPO₄²⁻. Therefore H₃PO₄ is the strongest acid among the three species, making statement B true.


**Statement C:** For a polyprotic acid each successive deprotonation is less favorable because the negative charge on the conjugate base builds up, repelling the departing proton. Consequently

Ka1 > Ka2 > Ka3

This ordering is observed for phosphoric acid (Ka1 ≈ 7.5 × 10⁻³, Ka2 ≈ 6.2 × 10⁻⁸, Ka3 ≈ 4.8 × 10⁻¹³). Thus statement C is true.


**Statement D:** No theoretical or experimental relationship of the form

Ka1 = Ka3 + Ka2/2

exists for phosphoric acid. Substituting the actual values gives a clear mismatch (7.5 × 10⁻³ ≠ 4.8 × 10⁻¹³ + ½·6.2 × 10⁻⁸). Therefore statement D is false.


Since statements A, B, C are true and D is false, the correct option is **A, B and C only**.

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