Phosphoric acid ionizes in three steps with their ionization constant values Ka1,Ka2,Ka3, respectively, while K is the overall ionization constant. Which of the following statements are true?
A. log K = log Ka1 + logKa2 + logKa3
B. H3PO4 is a stronger acid than H2PO4- and HPO2-4
C. Ka1 > Ka2 > Ka3
D. Ka1 = Ka3 + Ka2/2
Choose the correct answer from the options given below :
Correct Answer :
A, B and C only
Solution :
**Statement A:** The overall ionization constant K for phosphoric acid is the product of the three stepwise constants:
Taking the base‑10 logarithm of both sides gives
Hence statement A is true.
**Statement B:** The first dissociation of phosphoric acid is
Since Ka1 (≈ 7.5 × 10⁻³) is larger than Ka2 and Ka3, the parent acid H₃PO₄ donates a proton more readily than its conjugate bases H₂PO₄⁻ and HPO₄²⁻. Therefore H₃PO₄ is the strongest acid among the three species, making statement B true.
**Statement C:** For a polyprotic acid each successive deprotonation is less favorable because the negative charge on the conjugate base builds up, repelling the departing proton. Consequently
This ordering is observed for phosphoric acid (Ka1 ≈ 7.5 × 10⁻³, Ka2 ≈ 6.2 × 10⁻⁸, Ka3 ≈ 4.8 × 10⁻¹³). Thus statement C is true.
**Statement D:** No theoretical or experimental relationship of the form
exists for phosphoric acid. Substituting the actual values gives a clear mismatch (7.5 × 10⁻³ ≠ 4.8 × 10⁻¹³ + ½·6.2 × 10⁻⁸). Therefore statement D is false.
Since statements A, B, C are true and D is false, the correct option is **A, B and C only**.
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