Question Details

Rate of reaction of nucleophilic substitution in polar protic solvent is:

Options

A

B > A > D > C

B

C > D > A > B

C

A > B > C > D

D

D > A > B > C

Show Answer

Correct Answer :

Option A

B > A > D > C

Solution :

Correct Option: B > A > D > C


Concept and Mechanism:

In a polar protic solvent, nucleophilic substitution for benzylic halides predominantly proceeds via the SN1 mechanism. The rate-determining step (RDS) in an SN1 reaction involves the ionization of the substrate to form a carbocation intermediate:

R-BrslowR++Br-

Therefore, the rate of nucleophilic substitution is directly proportional to the stability of the carbocation formed at the benzylic carbon.


Analyzing the Structures given in the image:


Upon cleavage of the C-Br bond, each compound forms a benzylic carbocation (Ar-CH2+) stabilized or destabilized by substituents attached to the benzene ring:

1. Structure (B) [p-amino benzyl bromide]: The para-NH2 group exerts a powerful +M (positive mesomeric/resonance) effect, donating lone pair electrons into the ring and strongly stabilizing the positive charge of the carbocation.

2. Structure (A) [p-hydroxy benzyl bromide]: The para-OH group also exerts a +M effect, but the +M power of -NH2 is greater than -OH because nitrogen is less electronegative than oxygen. Thus, carbocation stability from (B) is greater than (A).

3. Structure (D) [m-nitro benzyl bromide]: The -NO2 group is strongly electron-withdrawing. At the meta-position, it exerts a strong -I (inductive) effect without resonance destabilization at the benzylic position, making it less stable than (A) and (B), but more stable than (C).

4. Structure (C) [p-nitro benzyl bromide]: The -NO2 group at the para-position exerts both strong -M (mesomeric) and -I (inductive) effects, strongly destabilizing the positive charge on the benzylic carbon. Hence, it forms the least stable carbocation.


Order of Carbocation Stability (and Reaction Rate):

B>A>D>C


Hence, the correct decreasing order of the rate of nucleophilic substitution in a polar protic solvent is B > A > D > C.

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