Reaction of aniline with conc. HNO₃ and conc. H₂SO₄ at 298 K will produce 47% of

The correct option is p-Nitroaniline.

Explanation:
When aniline is treated with a nitrating mixture containing concentrated nitric acid (conc. $HN{O}_3$) and concentrated sulfuric acid (conc. $H{S}_2{O}_4$) at 298 K, it undergoes electrophilic aromatic substitution (nitration).

Under these strongly acidic conditions, a significant portion of aniline is protonated to form the anilinium ion:
$C_6{H}_5-N{H}_2+H^{+}\rightleftharpoons C_6{H}_5-N{H}_3^{+}$
The positively charged $-N{H}_3^{+}$ group is electron-withdrawing and deactivating, directing the incoming nitronium ion electrophile ($N{O}_2^{+}$) to the meta-position.

At the same time, the unprotonated aniline remains highly reactive and directs substitution to the ortho and para positions due to the electron-donating resonance effect of the lone pair on the nitrogen atom.

As a result, a mixture of three isomeric nitroanilines is obtained in the following approximate yields:
1. p-Nitroaniline (para product)
2. m-Nitroaniline (meta product)
3. o-Nitroaniline (ortho product)

According to the reaction stoichiometry and standard experimental conditions, p-nitroaniline and m-nitroaniline form the bulk of the products, with p-nitroaniline designated as the correct option here.