Read the following information carefully and answer the questions given below:

Eight persons — A, B, C, D, E, F, G and H — were born on two different dates i.e. 11th and 20th of four different months viz. August, October, November and December of the same year. No two persons were born on the same day.

G was born four persons before B. B was born in the month having even number of days. E was born two persons after G. A was born three persons before E. F was born in the month having even number of days. F was born after C. D was born on an odd number date.

How many persons were after H?

The correct option is None.

Let's solve the arrangement step-by-step based on the given clues.

1. Understanding the Setup:
There are 8 positions corresponding to two dates (11th and 20th) in four different months (August, October, November, and December):
1. August 11 (31 days)
2. August 20 (31 days)
3. October 11 (31 days)
4. October 20 (31 days)
5. November 11 (30 days - even number of days)
6. November 20 (30 days - even number of days)
7. December 11 (31 days)
8. December 20 (31 days)

2. Analyzing Clues for B, G, E, and A:
• B was born in a month having an even number of days, which means B was born in November (either November 11 or November 20).
• G was born four persons before B. This means there are 3 persons between G and B (Position of G = Position of B - 4).
• E was born two persons after G (Position of E = Position of G + 2).
• A was born three persons before E (Position of A = Position of E - 3).

Let's test the two possible cases for B:

Case 1: B is born on November 20 (Position 6)
• G = Position 6 - 4 = Position 2 (August 20)
• E = Position 2 + 2 = Position 4 (October 20)
• A = Position 4 - 3 = Position 1 (August 11)
This is a valid arrangement of positions!

Case 2: B is born on November 11 (Position 5)
• G = Position 5 - 4 = Position 1 (August 11)
• E = Position 1 + 2 = Position 3 (October 11)
• A = Position 3 - 3 = Position 0 (Not possible since positions start at 1).
Hence, Case 2 is invalid.

3. Determining Remaining Positions (C, D, F, H):
From Case 1, we currently have:
• Position 1 (Aug 11): A
• Position 2 (Aug 20): G
• Position 3 (Oct 11): Empty
• Position 4 (Oct 20): E
• Position 5 (Nov 11): Empty
• Position 6 (Nov 20): B
• Position 7 (Dec 11): Empty
• Position 8 (Dec 20): Empty

Remaining empty dates: Oct 11, Nov 11, Dec 11, Dec 20.
• D was born on an odd number date. The remaining odd number dates are Oct 11, Nov 11, Dec 11.
• F was born in a month having an even number of days. November is the only month with an even number of days (30 days) that has an empty slot (Nov 11). Thus, F is born on November 11 (Position 5).
• F was born after C, which means C must be born before Nov 11. The only available slot before Nov 11 is October 11 (Position 3). So, C is born on October 11.
• Now, D must be born on an odd date among the remaining slots (Dec 11 and Dec 20). Thus, D is born on December 11 (Position 7).
• The last remaining person, H, must be born on the last available slot, December 20 (Position 8).

Final Order of Birth:
1. August 11 — A
2. August 20 — G
3. October 11 — C
4. October 20 — E
5. November 11 — F
6. November 20 — B
7. December 11 — D
8. December 20 — H

Question Analysis:
How many persons were after H?
Since H is at the very last position (December 20), there are None (0) persons born after H.