Read the following pie charts carefully and answer the questions given below.The pie chart (I) shows the percentage distribution of the total number of tickets sold by five different cinema halls on Sunday. The pie chart (II) shows the percentage distribution of the profit earned by these cinema halls on Sunday.

Note: The average profit of each ticket sold is Rs 30.

The total number of tickets sold by E and C together is what percentage more or less than the total number of tickets sold by B?

The correct answer is 60%.

Step-by-step Explanation:

Based on the provided pie chart (I) titled "Total tickets sold = 200", we can identify the percentage distribution of tickets sold by each cinema hall on Sunday:
- Cinema Hall A: $20\%$
- Cinema Hall B: $25\%$
- Cinema Hall C: $10\%$
- Cinema Hall D: $15\%$
- Cinema Hall E: $30\%$

We need to find what percentage more or less the total number of tickets sold by E and C together is than the total number of tickets sold by B. We can solve this using two methods.

Method 1: Using Percentages Directly

Since the base for all percentages in pie chart (I) is the same (the total tickets sold, which is 200), we can perform calculations directly with the percentage values.

1. Calculate the combined percentage of tickets sold by E and C together:
$\mathrm{Percentage}(E+C)=30\%+10\%=40\%$

2. Identify the percentage of tickets sold by B:
$\mathrm{Percentage}\left(B\right)=25\%$

3. Calculate the percentage difference relative to B:
$\text{Percentage More}=\frac{\mathrm{Percentage}(E+C)-\mathrm{Percentage}\left(B\right)}{\mathrm{Percentage}\left(B\right)}\times 100$

Substitute the values into the equation:
$\text{Percentage More}=\frac{40\%-25\%}{25\%}\times 100$

Simplify the fraction:
$\text{Percentage More}=\frac{15}{25}\times 100=\frac{3}{5}\times 100=60\%$

Method 2: Using the Number of Tickets

1. Find the total number of tickets sold by E and C:
- Tickets sold by E: $30\%\text{of}200=\frac{30}{100}\times 200=60$
- Tickets sold by C: $10\%\text{of}200=\frac{10}{100}\times 200=20$
- Combined tickets (E and C): $60+20=80$

2. Find the total number of tickets sold by B:
- Tickets sold by B: $25\%\text{of}200=\frac{25}{100}\times 200=50$

3. Calculate the percentage by which E and C together (80) is more than B (50):
$\text{Percentage More}=\frac{80-50}{50}\times 100$

Simplify the expression:
$\text{Percentage More}=\frac{30}{50}\times 100=0.6\times 100=60\%$

Thus, the total number of tickets sold by E and C together is 60% more than that sold by B.