Read the given information carefully and answer the questions based on it:

Six persons visit a place on two dates 11 and 22 in three different months i.e., September, October and November. They all like different colors viz. white, blue, pink, green, red and yellow but not necessarily in the same order as given.

The one who likes yellow visits three persons after L. L and S visit on same date and in the month of even numbered days. Two persons visit between S and R who likes green. Number of persons visit before R is same as the number of persons visit after V. The one who likes white visit just before H. No one visit between K and the one who likes blue. The one who likes red visits before the one who likes pink.

Which of the following color does S like?

To find the color that S likes, let us analyze the clues step-by-step and construct the scheduling table.

First, let us identify the months and the number of days in each:
1. September has 30 days (even numbered days).
2. October has 31 days (odd numbered days).
3. November has 30 days (even numbered days).

The visiting dates are the 11th and 22nd of each month. This gives us 6 chronological slots:
Slot 1: September 11
Slot 2: September 22
Slot 3: October 11
Slot 4: October 22
Slot 5: November 11
Slot 6: November 22

Step 1: Determine the positions of L and S
We are told that L and S visit on the same date and in a month with an even number of days (September and November). Since they visit in different months on the same date, they must both visit on either the 11th or the 22nd.
We are also given: "The one who likes yellow visits three persons after L."
This means if L is at Slot x, the yellow color is at Slot x + 3. Since there are only 6 slots, L must be at Slot 1 or Slot 2.

Let's analyze the two cases for the dates of L and S:
Case A: L and S visit on the 11th (Sept 11 and Nov 11)
Since L must be in September (to allow 3 slots after him), L is at Slot 1 (Sept 11) and S is at Slot 5 (Nov 11).
- Two persons visit between S (Slot 5) and R. This means R must be at Slot 2 (Sept 22).
- The number of persons visiting before R (1 person) is equal to the number of persons visiting after V. Thus, V must be at Slot 5. But S is already at Slot 5, which is a contradiction. Therefore, Case A is invalid.

Case B: L and S visit on the 22nd (Sept 22 and Nov 22)
Since L must be in September, L is at Slot 2 (Sept 22) and S is at Slot 6 (Nov 22).
- The one who likes yellow visits three persons after L, which places yellow at Slot 5 (2 + 3 = 5).
- Two persons visit between S (Slot 6) and R. This places R at Slot 3 (Oct 11). R likes Green.
- The number of persons visiting before R (2 persons: Slot 1 and Slot 2) is equal to the number of persons visiting after V. This places V at Slot 4 (Oct 22).

Let's summarize the positions determined so far in Case B:

Step 2: Place the remaining persons
The remaining empty slots for persons are Slot 1 and Slot 5. The remaining persons to place are H and K.
We are given: "The one who likes white visits just before H."
Since H cannot be at Slot 1 (no slot before it), H must be at Slot 5.
Consequently, the one who likes white must be at Slot 4 (V likes White).
This leaves K to be placed at Slot 1.

Step 3: Assign the remaining colors
- "No one visits between K and the one who likes blue." Since K is at Slot 1, the person at Slot 2 (L) must like Blue.
- The remaining slots without color assignments are Slot 1 (K) and Slot 6 (S). The remaining colors are Red and Pink.
- "The one who likes red visits before the one who likes pink." Since Slot 1 comes before Slot 6, K (Slot 1) likes Red, and S (Slot 6) likes Pink.

The final completed schedule is:

Therefore, S likes the color Pink.