Read the given information carefully and answer the questions based on it:

Six persons visit a place on two dates 11 and 22 in three different months i.e., September, October and November. They all like different colors viz. white, blue, pink, green, red and yellow but not necessarily in the same order as given.

The one who likes yellow visits three persons after L. L and S visit on same date and in the month of even numbered days. Two persons visit between S and R who likes green. Number of persons visit before R is same as the number of persons visit after V. The one who likes white visit just before H. No one visit between K and the one who likes blue. The one who likes red visits before the one who likes pink.

Who among the following visit on 22 October?

To find out who visits on 22 October, let us organize the given information step-by-step.

1. Understand the Schedule Structure:
There are six slots across three months, with two dates (11 and 22) each:
1. September 11 (30 days)
2. September 22 (30 days)
3. October 11 (31 days)
4. October 22 (31 days)
5. November 11 (30 days)
6. November 22 (30 days)

2. Analyze the Clues for L and S:
- L and S visit on the same date in months with even numbered days (September and November have 30 days, whereas October has 31 days).
- This means one of them visits in September and the other in November, both on either the 11th or the 22nd.
- The one who likes yellow visits three persons after L (L is at position $x$ and Yellow is at position $x+3$).
- Since Yellow must be within the 6 positions, L can only be at position 1 (September 11) or position 2 (September 22). Therefore, L must visit in September.

Let's evaluate the two possible cases:

Case 1: L visits on September 11 and S visits on November 11 (both on the 11th).
- L is at position 1 (September 11).
- Yellow visits 3 persons after L, which is position 4 (October 22).
- S is at position 5 (November 11).
- Two persons visit between S and R (who likes green). R must be at position 2 (September 22).
- The number of persons visiting before R (1 person, i.e., L) is the same as the number of persons visiting after V. This means V must be at position 5 (November 11).
- However, position 5 is already occupied by S. This is a contradiction, so Case 1 is invalid.

Case 2: L visits on September 22 and S visits on November 22 (both on the 22nd).
- L is at position 2 (September 22).
- Yellow visits 3 persons after L, which is position 5 (November 11).
- S is at position 6 (November 22).
- Two persons visit between S (position 6) and R (who likes green). Thus, R is at position 3 (October 11).
- The number of persons visiting before R (2 persons, i.e., at positions 1 and 2) is the same as the number of persons visiting after V. This means 2 persons must visit after V, placing V at position 4 (October 22).

3. Complete the Arrangement:
- The remaining vacant positions for people are position 1 (September 11) and position 5 (November 11). The remaining people to place are H and K.
- "The one who likes white visits just before H." If H is at position 1, white would have to be at position 0, which is impossible. Thus, H is at position 5 (November 11), and the one who likes white is V at position 4 (October 22).
- Consequently, K is at position 1 (September 11).
- "No one visits between K and the one who likes blue." Since K is at position 1, the blue-liker must be at position 2 (L).
- "The one who likes red visits before the one who likes pink." Since the only remaining positions without colors are 1 (K) and 6 (S), K likes red and S likes pink.

Final Arrangement:
1. September 11: K (Red)
2. September 22: L (Blue)
3. October 11: R (Green)
4. October 22: V (White)
5. November 11: H (Yellow)
6. November 22: S (Pink)

Therefore, V visits on 22 October.