Question Details

Read the given information carefully and answer the questions based on it:

Six persons visit a place on two dates 11 and 22 in three different months i.e., September, October and November. They all like different colors viz. white, blue, pink, green, red and yellow but not necessarily in the same order as given.

The one who likes yellow visits three persons after L. L and S visit on same date and in the month of even numbered days. Two persons visit between S and R who likes green. Number of persons visit before R is same as the number of persons visit after V. The one who likes white visit just before H. No one visit between K and the one who likes blue. The one who likes red visits before the one who likes pink.

The one who likes blue, visit on which of the following date?

Options

A

22 October

B

11 November

C

11 October

D

22 November

E

22 September

Show Answer

Correct Answer :

Option E

22 September

22 September

Solution :

Step 1: Understand the Scheduling Slots
There are six persons visiting on two dates (11 and 22) in three months (September, October, and November). Since September and November have 30 days (even-numbered days) and October has 31 days (odd-numbered days), the chronological order of visits is:
1. 11 September
2. 22 September
3. 11 October
4. 22 October
5. 11 November
6. 22 November

Step 2: Place L and S
We are given that L and S visit on the same date in months with even-numbered days (September and November). Therefore, both L and S must visit either on the 11th or the 22nd of September and November.
We also know that the person who likes yellow visits three persons after L. This means L must visit in September (so that three slots after L exist).
This gives two cases:
Case 1: L visits on 11 September (Slot 1) and S visits on 11 November (Slot 5). The person who likes yellow would visit on 22 October (Slot 4).
Case 2: L visits on 22 September (Slot 2) and S visits on 22 November (Slot 6). The person who likes yellow would visit on 11 November (Slot 5).

Step 3: Analyze the positions of R and V
Two persons visit between S and R (who likes green):
• In Case 1: S is on 11 November (Slot 5). R must be on 22 September (Slot 2). The number of persons visiting before R is 1 (11 September). Thus, the number of persons visiting after V must also be 1, meaning V visits on 11 November (Slot 5). But S is already on 11 November, creating a conflict. Thus, Case 1 is eliminated.
• In Case 2: S is on 22 November (Slot 6). R (green) must be on 11 October (Slot 3). The number of persons visiting before R is 2 (11 and 22 September). Thus, the number of persons visiting after V must also be 2, meaning V visits on 22 October (Slot 4).

Step 4: Place the remaining persons and colors
In Case 2, we have the following assignments so far:
• 11 September: [Empty]
• 22 September: L
• 11 October: R (Green)
• 22 October: V
• 11 November: [Empty] (Yellow)
• 22 November: S

We are told that the one who likes white visits just before H.
If White was at 11 September, H would have to be L (22 September), which is possible. But K and the one who likes blue visit with no one between them. If K is at 11 September, L is next to K. Since L is next to K, L must like blue.
If White was at 22 October (V), then H must be at 11 November. This fits perfectly: V likes White, and H is at 11 November (who likes yellow).
This leaves K to visit on 11 September.
Since no one visits between K (11 September) and the one who likes blue, the person visiting on 22 September (L) must be the one who likes blue.

Step 5: Finalize the preferences
Finally, we know that the one who likes red visits before the one who likes pink. The remaining available color slots are for K (11 September) and S (22 November). Therefore, K likes red and S likes pink.
The final arrangement is:
• 11 September: K (Red)
22 September: L (Blue)
• 11 October: R (Green)
• 22 October: V (White)
• 11 November: H (Yellow)
• 22 November: S (Pink)

Thus, the one who likes blue visits on 22 September.

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