Read the given information carefully and answer the questions based on it:

Six persons visit a place on two dates 11 and 22 in three different months i.e., September, October and November. They all like different colors viz. white, blue, pink, green, red and yellow but not necessarily in the same order as given.

The one who likes yellow visits three persons after L. L and S visit on same date and in the month of even numbered days. Two persons visit between S and R who likes green. Number of persons visit before R is same as the number of persons visit after V. The one who likes white visit just before H. No one visit between K and the one who likes blue. The one who likes red visits before the one who likes pink.

Which of the following statement(s) is/are true?
I. The one who likes green is the last one to visit
II. H likes pink
III. More than two persons visit before V

To find the correct statement(s), we can construct a chronological schedule based on the given clues. The six visits happen on the 11th and 22nd of September (30 days), October (31 days), and November (30 days).

Let us list the dates in chronological order:
1. September 11
2. September 22
3. October 11
4. October 22
5. November 11
6. November 22

Step 1: Determine the positions of L and S
L and S visit on the same date and in a month with even numbered days (September and November both have 30 days, while October has 31 days). This means L and S must visit on either the 11th of September and November, or the 22nd of September and November.
The one who likes yellow visits three persons after L. Therefore, L must visit in September (either position 1 or 2) so that three persons after L (position 4 or 5) is within the schedule.
Let's analyze the two cases:

Case 1: L visits on September 11 (Position 1)
- S visits on November 11 (Position 5).
- The one who likes yellow visits on October 22 (Position 4).
- Two persons visit between S (5) and R (who likes green). So, R must be at Position 2 (September 22).
- The number of persons visiting before R (1 person) is the same as the number of persons visiting after V. Thus, V must be at Position 5 (November 11). But S is already at Position 5, which is a contradiction. Hence, Case 1 is invalid.

Case 2: L visits on September 22 (Position 2)
- S visits on November 22 (Position 6).
- The one who likes yellow visits on November 11 (Position 5).
- Two persons visit between S (6) and R (who likes green). So, R must be at Position 3 (October 11).
- The number of persons visiting before R (2 persons: Positions 1 and 2) is the same as the number of persons visiting after V. Thus, V must be at Position 4 (October 22). This works perfectly.

Step 2: Placing the remaining persons and colors
- The current schedule by position is:
1. [Name?], [Color?]
2. L, [Color?]
3. R, Green
4. V, [Color?]
5. [Name?], Yellow
6. S, [Color?]
- "The one who likes white visits just before H." This means White and H are at consecutive positions. The only available consecutive spots where the first has no color and the second has no name is Position 4 (V) and Position 5 (H). Thus, V likes White, and H is at Position 5 (who likes Yellow).
- Now, the remaining name K must be at Position 1.
- "No one visits between K (Position 1) and the one who likes blue." This means the person at Position 2 (L) likes Blue.
- "The one who likes red visits before the one who likes pink." The remaining positions for colors are Position 1 and Position 6. Thus, K (1) likes Red and S (6) likes Pink.

Final Arrangement:
1. September 11: K, Red
2. September 22: L, Blue
3. October 11: R, Green
4. October 22: V, White
5. November 11: H, Yellow
6. November 22: S, Pink

Evaluating the Statements:
- I. The one who likes green is the last one to visit: False, S (who likes pink) is the last one to visit.
- II. H likes pink: False, H likes yellow.
- III. More than two persons visit before V: True, 3 persons (K, L, and R) visit before V (who visits at Position 4).

Therefore, only statement III is true.