Read the given information carefully and answer the following questions.

Six persons A to F were born on the same date in October in six different years, namely 1980, 1985, 1988, 1992, 1995, and 1998. Their ages are calculated as of 2026. Each person likes a different color among Red, Blue, Green, Yellow, Orange, and Purple. All the above information is not necessarily in the same order.

A is the oldest person. The one who likes Green is younger than the one who likes Red, and the difference between their ages is 8. Two persons were born between the one who likes Blue and E. D was born immediately before E, who likes Orange. The sum of the digits of the year in which F was born is 27.

How many persons were born between the one who likes Yellow and A?

Step 1: Calculate the ages of each person as of the year 2026 based on their birth years.

• Birth year 1980: Age = 2026 - 1980 = 46
• Birth year 1985: Age = 2026 - 1985 = 41
• Birth year 1988: Age = 2026 - 1988 = 38
• Birth year 1992: Age = 2026 - 1992 = 34
• Birth year 1995: Age = 2026 - 1995 = 31
• Birth year 1998: Age = 2026 - 1998 = 28

Step 2: Determine the positions of the individuals based on the given clues.

1. "A is the oldest person."
Since the oldest person was born in 1980 (Age 46), A was born in 1980.

2. "The sum of the digits of the year in which F was born is 27."
Let's check the sum of the digits for each birth year:
• 1980: 1 + 9 + 8 + 0 = 18
• 1985: 1 + 9 + 8 + 5 = 23
• 1988: 1 + 9 + 8 + 8 = 26
• 1992: 1 + 9 + 9 + 2 = 21
• 1995: 1 + 9 + 9 + 5 = 24
• 1998: 1 + 9 + 9 + 8 = 27
Thus, F was born in 1998.

3. "D was born immediately before E, who likes Orange."
This means D and E must occupy two consecutive birth years in the order (D, E).
The available available consecutive years (ignoring A = 1980 and F = 1998) are:
- 1985 and 1988
- 1988 and 1992 (Not consecutive years)
- 1992 and 1995
Let's also use the clue: "Two persons were born between the one who likes Blue and E."

Let's test the possibilities for D and E:
• Case 1: D in 1985, E in 1988 (E likes Orange).
Two persons between Blue and E (1988) would mean Blue must be in 1998 (since 1980 is only 2 persons before 1988, wait: between 1988 and 1980 there is 1 person (1985), between 1988 and 1998 there are 2 persons: 1992, 1995). So Blue = 1998 (F).
Let's check the age difference of 8 between Red and Green ("The one who likes Green is younger than the one who likes Red, and the difference between their ages is 8"):
Ages: 46, 41, 38, 34, 31, 28.
Age differences of 8: 46 - 38 = 8 (Red = 46/1980, Green = 38/1988 - but 1988 is E who likes Orange, conflict!).
Other age difference of 8: 39? No other pair has a difference of 8 (41-33 no, 38-30 no, 34-26 no, 31-23 no).
So Red = 1980 (Age 46) and Green = 1988 (Age 38). But E (1988) likes Orange, so Green cannot be in 1988. Thus, Case 1 is invalid.

• Case 2: D in 1992, E in 1995 (E likes Orange).
Two persons between E (1995) and Blue: 2 persons born before 1995 are 1988 and 1992. So the person born in 1985 must like Blue!
Now let's check the Red and Green clue: Age difference is 8, Red is older than Green.
As established, the only pair with an age difference of 8 is 46 (1980) and 38 (1988).
Therefore, Red = 1980 (A) and Green = 1988.
This works perfectly!

Step 3: Complete the arrangement.

Birth Years & Persons:
• 1980 (Age 46): A -> Red
• 1985 (Age 41): B/C -> Blue
• 1988 (Age 38): B/C -> Green
• 1992 (Age 34): D -> Yellow (the only remaining color)
• 1995 (Age 31): E -> Orange
• 1998 (Age 28): F -> Purple / Yellow

Since D is born in 1992, D likes Yellow.
The person who likes Yellow was born in 1992.
A was born in 1980.

Step 4: Count the number of persons born between the one who likes Yellow (1992) and A (1980).

The persons born between 1980 and 1992 are those born in 1985 and 1988.
Thus, exactly 2 persons were born between the one who likes Yellow and A.

The correct option is Two.