Read the given information carefully and answer the questions below:
1%2 means 2 is neither smaller nor greater than 1
1&2 means 2 is neither greater nor equal to 1
1*2 means 2 is neither smaller nor equal to 1
1$2 means 2 is not greater than 1
1α2 means 2 is not smaller than 1
Statements: U$LαK%T; W&P; D*J; W%R$L; M*TαJ
Conclusions: I. M*W II. D&K III. J$P
Correct Answer :
None is true
Solution :
Correct Answer: None is true
To solve this coded inequality question, let us first decode the given symbols according to the instructions provided:
1. 1%2 means 2 is neither smaller nor greater than 1 ⇒ 2 = 1 (or 1 = 2).
2. 1&2 means 2 is neither greater nor equal to 1 ⇒ 2 < 1 (which means 1 > 2).
3. 1*2 means 2 is neither smaller nor equal to 1 ⇒ 2 > 1 (which means 1 < 2).
4. 1$2 means 2 is not greater than 1 ⇒ 2 ≤ 1 (which means 1 ≥ 2).
5. 1α2 means 2 is not smaller than 1 ⇒ 2 ≥ 1 (which means 1 ≤ 2).
Now, let us rewrite the given relations for two elements A and B where A [symbol] B:
• A % B ⇒ A = B
• A & B ⇒ A > B
• A * B ⇒ A < B
• A $ B ⇒ A ≥ B
• A α B ⇒ A ≤ B
Given Statements:
• U $ L α K % T ⇒ U ≥ L, L ≤ K, K = T ⇒ U ≥ L ≤ K = T
• W & P ⇒ W > P
• D * J ⇒ D < J
• W % R $ L ⇒ W = R ≥ L
• M * T α J ⇒ M < T ≤ J
Combining the relevant statements to check each conclusion:
Conclusion I: M * W
M * W means M < W.
Combining the path between M and W:
M < T = K ≥ L ≤ R = W
Since the symbols between T and R change direction (K ≥ L ≤ R), there is no definite relationship between M and W. Thus, Conclusion I does not follow.
Conclusion II: D & K
D & K means D > K.
Combining the path between D and K:
D < J ≥ T = K
Since the symbols between D and K change direction (D < J ≥ T), there is no definite relationship between D and K. Thus, Conclusion II does not follow.
Conclusion III: J $ P
J $ P means J ≥ P.
Connecting J and P:
J ≥ T = K ≥ L ≤ R = W > P
Here also, opposite sign directions exist between J and P (K ≥ L ≤ R). Hence, no definite relationship can be established between J and P. Thus, Conclusion III does not follow.
Therefore, none of the conclusions I, II, or III are true.
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