Refer to the following number series and answer the question that follows (all numbers
are single-digit numbers only). Counting to be done from left to right only.
(Left) 6 5 8 8 5 4 7 7 4 2 7 9 2 2 5 7 4 8 8 2 1 8 9 (Right)
How many such odd digits are there, each of which is immediately preceded by an odd
digit and also immediately followed by an odd digit?

Correct Option: none

Step-by-Step Explanation:

We are given the following number series (counting from Left to Right):

(Left) 6 5 8 8 5 4 7 7 4 2 7 9 2 2 5 7 4 8 8 2 1 8 9 (Right)

We need to find the total count of odd digits that satisfy the following condition:

(Odd Digit) - [Target Odd Digit] - (Odd Digit)

That is, the digit must be odd, and both its immediate left neighbor and immediate right neighbor must also be odd digits.

Let's identify all odd digits in the series (1, 3, 5, 7, 9) and check their surrounding neighbors:

1. The first 5 (position 2): Preceded by 6 (even). Does not satisfy the condition.
2. The second 5 (position 5): Preceded by 8 (even) and followed by 4 (even). Does not satisfy.
3. The first 7 (position 7): Preceded by 4 (even). Does not satisfy.
4. The second 7 (position 8): Preceded by 7 (odd), but followed by 4 (even). Does not satisfy.
5. The third 7 (position 11): Preceded by 2 (even). Does not satisfy.
6. The first 9 (position 12): Preceded by 7 (odd), but followed by 2 (even). Does not satisfy.
7. The third 5 (position 15): Preceded by 2 (even). Does not satisfy.
8. The fourth 7 (position 16): Preceded by 5 (odd), but followed by 4 (even). Does not satisfy.
9. The only 1 (position 21): Preceded by 2 (even). Does not satisfy.
10. The second 9 (position 23): Preceded by 8 (even) and is the last digit. Does not satisfy.

None of the odd digits in the series are both preceded and followed by an odd digit.

Therefore, the required count is none.