Question Details

Savitha notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as: (Take π2 = 9.8, and g =9.8 m/s2)

Options

A

2 m

B

1 m

C

0.75 m

D

1.5 m

Show Answer

Correct Answer :

Option B

1 m

1 m

Solution :

Given that 30 complete oscillations take a total time of 60 s, the period T (time for one oscillation) is

T = \frac{60\ \text{s}}{30} = 2\ \text{s}

The period of a simple pendulum of length L is related to the acceleration due to gravity g by

T = 2\,\pi\,\sqrt{\frac{L}{g}}

Re‑arranging to solve for L gives

L = g\,\left(\frac{T}{2\,\pi}\right)^{\!2}

Substituting T = 2\ \text{s}, g = 9.8\ \text{m/s}2 and the given numerical relation π2 = 9.8 (so π2 = g), we obtain

L = \frac{g\,T^{\!2}}{4\,\pi^{2}}

Plugging the numbers:

L = \frac{9.8 \times (2)^{2}}{4 \times 9.8}

Calculate numerator: 9.8 \times 4 = 39.2

Denominator: 4 \times 9.8 = 39.2

Therefore

L = \frac{39.2}{39.2} = 1\ \text{m}

Thus the length of the pendulum calculated by Savitha is 1 m.

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