Question Details

Select the reagents that reduce nitriles to primary amines


A. LiAlH4,H2O
B. Sn+HCl
C. H2/Ni
D. Na(Hg)/C2H5OH
E. Br2/aq.NaOH

Options

A

A, B and C only

B

A, C and D only

C

A, D and E only

D

B, D and E only

Show Answer

Correct Answer :

Option B

A, C and D only

A, C and D only

Solution :

To determine which reagents convert a nitrile (R‑C≡N) into a primary amine (R‑CH₂NH₂), we examine the typical reaction pathways of each reagent.

Reagent A: LiAlH4, H2O
LiAlH4 is a very strong hydride donor. In the presence of water it supplies four equivalents of H⁻, which attack the electrophilic carbon of the nitrile carbon‑nitrogen triple bond. The sequence is:

R‑C≡N + 4 H⁻ → R‑CH₂NH₂ + Al(OH)4

The nitrile is reduced directly to a primary amine without forming an intermediate aldehyde or imine that escapes reduction. Hence LiAlH4/H2O works.

Reagent B: Sn + HCl
Tin metal in acidic solution is a modest reducing system. It typically reduces nitriles to aldehydes (the “Tin/ HCl” reduction) rather than to amines. The aldehyde can be further reduced only under stronger conditions. Therefore Sn/HCl does **not** give a primary amine.

Reagent C: H2/Ni
Catalytic hydrogenation over nickel provides molecular hydrogen in a highly activated form. The nitrene‑like carbon of a nitrile undergoes successive hydrogen addition:

R‑C≡N + 2 H₂ → R‑CH₂NH₂

Both the C≡N bond and the resulting imine intermediate are fully hydrogenated, yielding the primary amine. Thus H2/Ni is suitable.

Reagent D: Na(Hg)/C2H5OH
Sodium amalgam in ethanol is a classic “Birch‑type” single‑electron‑transfer reducer. It reduces nitriles by delivering electrons and protons from the solvent, ultimately forming a primary amine:

R‑C≡N + 4 e⁻ + 4 H⁺ → R‑CH₂NH₂

This method is widely used for converting nitriles to primary amines, so D is effective.

Reagent E: Br2/aq NaOH
Bromine in aqueous alkali performs an oxidative halogenation that converts nitriles into carboxylic acids via the “haloform‑type” pathway, not into amines. Consequently, E does not achieve the desired transformation.

Summarizing the above A, C and D only

To determine which reagents convert a nitrile (R‑C≡N) into a primary amine (R‑CH₂NH₂), we examine the typical reaction pathways of each reagent.

Reagent A: LiAlH4, H2O
LiAlH4 is a very strong hydride donor. In the presence of water it supplies four equivalents of H⁻, which attack the electrophilic carbon of the nitrile carbon‑nitrogen triple bond. The sequence is:

R‑C≡N + 4 H⁻ → R‑CH₂NH₂ + Al(OH)4

The nitrile is reduced directly to a primary amine without forming an intermediate aldehyde or imine that escapes reduction. Hence LiAlH4/H2O works.

Reagent B: Sn + HCl
Tin metal in acidic solution is a modest reducing system. It typically reduces nitriles to aldehydes (the “Tin/ HCl” reduction) rather than to amines. The aldehyde can be further reduced only under stronger conditions. Therefore Sn/HCl does **not** give a primary amine.

Reagent C: H2/Ni
Catalytic hydrogenation over nickel provides molecular hydrogen in a highly activated form. The nitrene‑like carbon of a nitrile undergoes successive hydrogen addition:

R‑C≡N + 2 H₂ → R‑CH₂NH₂

Both the C≡N bond and the resulting imine intermediate are fully hydrogenated, yielding the primary amine. Thus H2/Ni is suitable.

Reagent D: Na(Hg)/C2H5OH
Sodium amalgam in ethanol is a classic “Birch‑type” single‑electron‑transfer reducer. It reduces nitriles by delivering electrons and protons from the solvent, ultimately forming a primary amine:

R‑C≡N + 4 e⁻ + 4 H⁺ → R‑CH₂NH₂

This method is widely used for converting nitriles to primary amines, so D is effective.

Reagent E: Br2/aq NaOH
Bromine in aqueous alkali performs an oxidative halogenation that converts nitriles into carboxylic acids via the “haloform‑type” pathway, not into amines. Consequently, E does not achieve the desired transformation.

Summarizing the above analysis, the reagents that successfully reduce nitriles to primary amines are:

A (LiAlH4/H2O), C (H2/Ni) and D (Na(Hg)/C2H5OH) only.

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