Seven persons S, E, V, B, A, D and U sit in a row facing north and they all work in a company with different working experience of 15yr, 7yr, 2yr, 23yr, 19yr, 6yr and 12yr. All the information is not necessarily in the same order as given.

The persons with vowel name have experience of even number year and neither sits at the end nor at exactly middle of the row. Three persons sit between S and the one having 23yr experience. One person sits between S and A. The number of persons sits to the right of A is same as the number of persons sits to the left of the one having experience 2.5 times of A. B neither have highest year experience nor sits adjacent to S. The person having least experience sits second to the left of D. U does not have least experience. The neighbors of B have more experience than B.

Who among the following sit second from left end of the row and with how much experience?

The correct option is E, 2yr.

Let's solve the linear seating arrangement step-by-step based on the given clues.

Step 1: Understand the given details

There are 7 persons: S, E, V, B, A, D, U sitting in a row facing North.
The given work experiences (in years) are: 2yr, 6yr, 7yr, 12yr, 15yr, 19yr, 23yr.

Step 2: Identify Experience for Vowel Named Persons

Persons with vowel names are E, A, U.
Even number years available are: 2yr, 6yr, 12yr.
Thus, E, A, U must have experiences from {2yr, 6yr, 12yr}.
Also, E, A, U neither sit at the extreme ends nor at the exact middle (4th position from either end).

Step 3: Analyze A's experience and the related clue

Clue: "The number of persons sits to the right of A is same as the number of persons sits to the left of the one having experience 2.5 times of A."
Since A's experience is an even number from {2, 6, 12}:
If A = 2yr, then 2.5 × 2 = 5yr (Not in the given list).
If A = 6yr, then 2.5 × 6 = 15yr (Valid, as 15yr is present in the list).
If A = 12yr, then 2.5 × 12 = 30yr (Not in the list).
Therefore, A = 6yr, and the person with 15yr experience corresponds to this condition.
This means: (Persons to the right of A) = (Persons to the left of the one with 15yr experience).

Step 4: Determine Positions of S, A, and 23yr

Let the 7 positions from left to right be 1, 2, 3, 4, 5, 6, 7.
Vowels (E, A, U) cannot sit at positions 1, 4, or 7. So vowels can only sit at positions 2, 3, 5, or 6.
"Three persons sit between S and the one having 23yr experience."
"One person sits between S and A."

Case 1: S is at position 1.
Then the person with 23yr experience is at position 5.
Since one person sits between S and A, A must be at position 3.
If A is at position 3, there are 4 persons to the right of A.
So the person with 15yr experience must have 4 persons to their left, putting them at position 5. But position 5 already has 23yr experience (Contradiction).

Case 2: S is at position 7.
Then the person with 23yr experience is at position 3.
Since one person sits between S and A, A must be at position 5.
If A is at position 5, there are 2 persons to the right of A.
So the person with 15yr experience must have 2 persons to their left, putting them at position 3. But position 3 already has 23yr experience (Contradiction).

Case 3: S is at position 2.
Then 23yr experience is at position 6.
A can be at position 4. But A is a vowel, so A cannot be at position 4 (middle position). (Invalid)

Case 4: S is at position 6.
Then 23yr experience is at position 2.
A can be at position 4 (middle position), which is invalid for vowels.

Case 5: 23yr experience is at position 1, S is at position 5.
Since one person sits between S and A, A can be at position 3 or position 7.
Since A cannot be at an end position (7), A must be at position 3.
With A at position 3:
- Persons to the right of A = 4.
- Person with 15yr experience is at position 5 (same position as S). Thus, S = 15yr.
Let's check positions so far:
1: [23yr]
2: Vowel (E/U)
3: A (6yr)
4: Consonant (V/B/D)
5: S (15yr)
6: Vowel (E/U)
7: Consonant (V/B/D)

Step 5: Determine positions for Least Experience (2yr), D, U, and E

Least experience is 2yr (which belongs to a vowel, so it must be E or U).
"The person having least experience sits second to the left of D."
So, Person(2yr) is 2 places to the left of D.
- If 2yr is at position 2: D must be at position 4.
- If 2yr is at position 3: A has 6yr, so 3 cannot be 2yr.
- If 2yr is at position 6: D would be at position 8 (out of bounds).
Thus, position 2 has 2yr experience, and position 4 is D.
Since U does not have least experience (2yr), position 2 must be E (2yr)!
This automatically places U at position 6.

Step 6: Assign remaining experiences and persons

Even experience values: A = 6yr, E = 2yr.
The remaining even experience value is 12yr, which must belong to U = 12yr (at position 6).

Remaining persons to place: B and V for positions 1 and 7.
Clue: "B neither have highest year experience (23yr) nor sits adjacent to S."
Position 1 has 23yr experience, so B cannot be at position 1. Also position 5 is S, so adjacent positions 4 and 6 are filled by D and U.
Therefore, B must be at position 7, and V must be at position 1 (V = 23yr).

Clue: "The neighbors of B have more experience than B."
The only neighbor of B (at position 7) is U (at position 6), who has 12yr.
Since U (12yr) > B, B must have an experience less than 12yr.
The remaining experiences are 7yr and 19yr.
Thus, B = 7yr and D = 19yr.

Final Seating Arrangement:

Position 1: V (23yr)
Position 2: E (2yr)
Position 3: A (6yr)
Position 4: D (19yr)
Position 5: S (15yr)
Position 6: U (12yr)
Position 7: B (7yr)

Thus, the person sitting second from the left end of the row is E with 2yr experience.