Six students - A, B, C, D, E and F - are sitting around a circular table, facing the centre.

A is the immediate neighbour of both E and F.

B is sitting second to the right of E.

D is sitting third to the left of F.

C is the immediate neighbour of both B and F.

Who among the following is the immediate neighbour of both A and D?

The correct answer is E.

Let us solve this step-by-step by placing the six students (A, B, C, D, E, and F) around a circular table facing the centre. Facing the centre means that for any person, "left" is in the clockwise direction and "right" is in the counter-clockwise direction.

Step 1: Place A, E, and F
We are given that A is the immediate neighbour of both E and F. This means A must sit between E and F.
Let us place A at Position 1.
Now, we have two possibilities for E and F:
- Case 1: E is to the immediate right of A (Position 2) and F is to the immediate left of A (Position 6).
- Case 2: F is to the immediate right of A (Position 2) and E is to the immediate left of A (Position 6).
Let us proceed with Case 1 first.

Step 2: Place B
We are given that B is sitting second to the right of E.
In Case 1, E is at Position 2. Counting two positions to the right (counter-clockwise) from E:
- First to the right is Position 3.
- Second to the right is Position 4.
Therefore, B sits at Position 4.

Step 3: Place D
We are given that D is sitting third to the left of F.
In a circle of 6 people, sitting "third to the left" (or third to the right) means sitting directly opposite. Since F is at Position 6, D must be opposite F at Position 3.

Step 4: Place C and verify the final condition
The only remaining seat is Position 5, so C must be placed there.
Let us verify the last clue: C is the immediate neighbour of both B and F.
With C at Position 5, B at Position 4, and F at Position 6, C is indeed sitting between B and F. This confirms our arrangement is correct.

The final clockwise seating arrangement is:
1. A
2. E
3. D
4. B
5. C
6. F

Conclusion:
Looking at the arrangement, the person sitting between A (Position 1) and D (Position 3) is E (Position 2). Therefore, E is the immediate neighbour of both A and D.