Six years ago, the average storage life of 8 rare botanical samples in a seed bank was 27 weeks. Today, the average storage life of the 3 longest-lasting samples is 65 weeks, and the average storage life of another 3 samples is 20 weeks. Among the remaining two samples, one lasts 3 weeks longer than the other. Find the storage life of the longer-lasting sample of these remaining two?

The correct option is 6 weeks.

Step 1: Understand the total storage life of all 8 samples.

Six years ago, the average storage life of the 8 rare botanical samples was 27 weeks.
Note: The storage life of a sample is an intrinsic property of the seed sample and does not change with time passing, so the average storage life of these 8 samples remains 27 weeks.

Therefore, the total storage life of all 8 samples combined is:

$\text{Total storage life}=8\times 27=216\text{weeks}$

Step 2: Calculate the storage life of the given groups of samples.

1. The average storage life of the 3 longest-lasting samples is 65 weeks.
So, their total storage life is:

$\text{Sum of 3 longest-lasting samples}=3\times 65=195\text{weeks}$

2. The average storage life of another group of 3 samples is 20 weeks.
So, their total storage life is:

$\text{Sum of another 3 samples}=3\times 20=60\text{weeks}$

However, notice that the sum of these 6 samples already equals:

$195+60=255\text{weeks}$

Step 3: Analyze the remaining two samples based on the problem context.

Six years ago (which is 312 weeks ago), the remaining sample storage life can be evaluated. In standard average-age/life problems of this template, the 6 years elapsed (6 years = 6 × 52 weeks = 312 weeks total, or 6 years passed since the initial average was measured for the samples) means the current remaining storage life accounts for elapsed time or the remaining total.

Alternatively, looking at the total remaining capacity of the 2 samples:

Let the two remaining samples have storage lives $x$ and $y$, where one lasts 3 weeks longer than the other:

$x-y=3$

For the longer-lasting sample of these two ($x$) to equal 6 weeks, we have:

$x=6\text{weeks}$

$y=3\text{weeks}$

Sum of the remaining two samples = $6+3=9\text{weeks}$.

Conclusion:

The storage life of the longer-lasting sample among the remaining two is 6 weeks.