Solve the numerical operations puzzle below.

If in the digit sequence “8367542741” we add 1 to the digits located at even positions and subtract 1 from the digits located at odd positions when scanning from the left, what will be the total sum of the 2nd, 4th, 7th, and 9th digits (from the left end) of the resulting sequence?

The correct option is 16.

Given Digit Sequence:
8367542741

Rules for Modification (scanning from left to right):
1. Subtract 1 from the digits located at odd positions (1st, 3rd, 5th, 7th, 9th).
2. Add 1 to the digits located at even positions (2nd, 4th, 6th, 8th, 10th).

Step-by-Step Modification of Each Digit:
- 1st position (Odd): 8 - 1 = 7
- 2nd position (Even): 3 + 1 = 4
- 3rd position (Odd): 6 - 1 = 5
- 4th position (Even): 7 + 1 = 8
- 5th position (Odd): 5 - 1 = 4
- 6th position (Even): 4 + 1 = 5
- 7th position (Odd): 2 - 1 = 1
- 8th position (Even): 7 + 1 = 8
- 9th position (Odd): 4 - 1 = 3
- 10th position (Even): 1 + 1 = 2

The resulting sequence is: 7458451832

Finding the Required Sum:
We need to add the 2nd, 4th, 7th, and 9th digits of the resulting sequence:
- 2nd digit = 4
- 4th digit = 8
- 7th digit = 1
- 9th digit = 3

Total Sum = 4 + 8 + 1 + 3 = 16

Therefore, the total sum is 16.