Question Details

Statement-I: He and Be have similar outer shell electronic configuration of type ns2.

Statement-II: He and Be are chemically inert.

Options

A

Statement I and Statement II both are correct.

B

Statement I is correct, but Statement II is incorrect.

C

Statement I is incorrect, but Statement II is correct.

D

Statement I and Statement II both are incorrect.

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Correct Answer :

Option B

Statement I is correct, but Statement II is incorrect.

Statement I is correct, but Statement II is incorrect.

Solution :

The correct answer is: Statement I is correct, but Statement II is incorrect.

Let us analyze each statement individually:

Statement I: "He and Be have similar outer shell electronic configuration of type ns2."

To verify this, we write out the electronic configurations of both elements:

Helium (He), atomic number 2: 1s2
The outermost (and only) shell is n = 1, and it has the configuration 1s2.

Beryllium (Be), atomic number 4: 1s2 2s2
The outermost shell is n = 2, and its valence configuration is 2s2.

In both cases, the outermost shell has the general electronic configuration ns2 (where n = 1 for He and n = 2 for Be). Both elements have their outermost s-orbital completely filled with 2 electrons.

Statement I is CORRECT.

Statement II: "He and Be are chemically inert."

Helium (He) is a noble gas. Its 1s2 configuration represents a completely filled shell (the first shell can hold a maximum of 2 electrons). This gives helium exceptional stability, making it chemically inert. Helium does not form compounds under normal conditions.

Beryllium (Be), on the other hand, is an alkaline earth metal belonging to Group 2 of the periodic table. Although its 2s2 subshell is fully filled, the second shell (n = 2) is not completely filled — it still has vacant 2p orbitals available. Beryllium can lose its two valence electrons to form Be2+ ions, or participate in covalent bonding (e.g., in BeCl2, BeF2, BeH2). Beryllium is therefore chemically reactive, not inert.

The key distinction is:
− For He, the entire shell (n = 1) is complete, giving true noble gas stability.
− For Be, only the 2s subshell is filled, but empty 2p orbitals in the same shell make it reactive.

Statement II is INCORRECT because while He is chemically inert, Be is definitely not.

Conclusion: Statement I is correct (both have ns2 outer configuration), but Statement II is incorrect (Be is chemically reactive, unlike He). Therefore, the correct option is: "Statement I is correct, but Statement II is incorrect."

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