Statements: C < G = L ≥ S > X ≤ A = F

Conclusions:
I. G > X
II. F > C

In this question, the relationship between different element is shown in the statements. The statements are followed by two conclusions. Give answer:

The correct option is If only conclusion I is true.

Step-by-Step Analysis:

Given statement: C < G = L ≥ S > X ≤ A = F

Let us evaluate each conclusion one by one:

Conclusion I: G > X
To find the relationship between G and X, let us trace the path from G to X in the statement:
G = L ≥ S > X
Since G = L, we can write:
G ≥ S > X
Comparing G and X across these inequalities, the strict inequality (>) dominates.
Therefore, G > X is true.

Conclusion II: F > C
To find the relationship between F and C, let us trace the path from C to F in the statement:
C < G = L ≥ S > X ≤ A = F
Notice the inequality signs between C and F: we have both < and > (opposite directions: C < G and S > X ≤ A).
When opposite inequality signs appear between two elements, no definite relationship can be established between them.
Therefore, F > C is false (or cannot be determined).

Hence, only conclusion I is true.