Study the following alphanumeric symbol series carefully and answer the questions given below:
F 4 A % T 9 µ Z M 3 N # L & E 2 X C 7 G D * O 5 R ∞ H 1 J $ @ K 8 B
What is the sum of the digits which are 3rd from the left end and 4th from the right end?
Correct Answer :
10
Solution :
The correct option is 10.
To find the required sum, let us analyze the given alphanumeric symbol series:
F 4 A % T 9 µ Z M 3 N # L & E 2 X C 7 G D * O 5 R ∞ H 1 J $ @ K 8 B
First, let us identify and list all the digits present in the series from left to right:
4, 9, 3, 2, 7, 5, 1, 8
Now, let us locate the specific digits as required by the question:
1. Digit which is 3rd from the left end:
Scanning the digits from the left end:
- 1st digit from left is 4
- 2nd digit from left is 9
- 3rd digit from left is 3
So, the 3rd digit from the left end is 3.
2. Digit which is 4th from the right end:
Scanning the digits from the right end:
- 1st digit from right is 8
- 2nd digit from right is 1
- 3rd digit from right is 5
- 4th digit from right is 7
So, the 4th digit from the right end is 7.
Finally, we calculate the sum of these two digits:
Thus, the sum of the digits is 10.
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